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hammer [34]
3 years ago
8

Solve for p 7/p = 8/9

Mathematics
2 answers:
klio [65]3 years ago
6 0
First, you cross multiply 7 x 9 and p x 9
You get
64 = 8x. Flip it to be 8x = 63
Then divide both sides, 8/8 cancels out
You get
X = 63/8
Marina CMI [18]3 years ago
5 0

Answer:

p= 63/8 or p=7.875 or p= 7 7/8

Step-by-step explanation:

That is what p is

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Mekhanik [1.2K]

According to unit circle the value of (0) is o

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3 years ago
Would each situation be represented by a positive or a negative number?
insens350 [35]
If 2 sodas and 4 hamburgers are $12.00 and 4 sodas and 2 hamburgers are $9.00 how much is a single hamburger?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ 

2s + 4h = 12, (1) 4s + 2h = 9. (2) Multiply (1) by 2. You will get 4s + 8h = 24, (1') 4s + 2h = 9. (2') Distract (2') from (1'). You will get 8h - 2h = 24 - 9, or 6h = 15 ---> h =  =  = 2.5. Thus one hamburger price is $2.50. Then from (1) s =  = 1. Answer. One hamburger price is $2.50 and 1 soda costs $1.00.

There is even more elegant way to solve the problem. 

Simply add all hamburgers and all sodas. 6 hamburgers and 6 sodas. $12 + $9 = $21. 

Hence, 1 hamburger + 1 soda =  = $3.50. 

Having this, everybody can solve to the end in this way, actually, without equations and using the mental math only. 


Question: A man measures the angle of elevation to the top of a mountain to be 12 degrees. He drives 7 miles closer and finds the angle of elevation to be 37 degrees. How high is the mountain? 
5 0
4 years ago
Simply the following expression 32 divided by (-2)
Musya8 [376]
32 divided by -2 equals -16. c:
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4 years ago
Use the Divergence Theorem to evaluate the following integral S F · N dS and find the outward flux of F through the surface of t
Xelga [282]

Answer:

Result;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = 32\pi

Step-by-step explanation:

Where:

F(x, y, z) = 2(x·i +y·j +z·k) and

S: z = 0, z = 4 -x² - y²

For the solid region between the paraboloid

z = 4 - x² - y²

div F        

For S: z = 0, z = 4 -x² - y²

We have the equation of a parabola

To verify the result for F(x, y, z) = 2(x·i +y·j +z·k)

We have for the surface S₁ the outward normal is N₁ = -k and the outward normal for surface S₂ is N₂ given by

N_2 = \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} }

Solving we have;

\int\limits\int\limits_S { \textbf{F}} \, \cdot \textbf{N} d {S} = \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{N}_1 d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot \textbf{N}_2 d {S}

Plugging the values for N₁ and N₂, we have

= \int\limits\int\limits_{S1} { \textbf{F}} \, \cdot \textbf{(-k)}d {S} + \int\limits\int\limits_{S2} { \textbf{F}} \, \cdot  \frac{2x \textbf{i} +2y \textbf{j} + \textbf{k}}{\sqrt{4x^2+4y^2+1} } d {S}

Where:

F(x, y, z) = 2(xi +yj +zk) we have

= -\int\limits\int\limits_{S1} 2z \ dA + \int\limits\int\limits_{S2} 4x^2+4y^2+2z \ dA

= -\int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 2z \ dA + \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2+2z \ dA

= \int\limits^2_{-2} \int\limits^{\sqrt{4-y^2}} _{-\sqrt{4-y^2}} 4x^2+4y^2 \ dxdy

= \int\limits^2_{-2} \frac{(16y^2 +32)\sqrt{-(y^2-4)} }{3} dy

= 32π.

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4 years ago
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<span>the answer is 2x^2+x+4 R 8/x+1</span>
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