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Shalnov [3]
3 years ago
13

What is the difference between 5 and 2 1/5

Mathematics
2 answers:
Vsevolod [243]3 years ago
3 0

The difference between 5 and 2 1/5

5 - 2 1/5

borrow from the 5

4 5/5 - 2 1/5

2 4/5

Answer: 2 4/5

ycow [4]3 years ago
3 0

Answer: 2.8 or 14/5


Step-by-step explanation: 5- 2 1/5 = 2.8 or 14/5


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Who had a head start, and how many miles was the head start? Rita had a 28-mile head start. Roger had a 26-mile head start. Roge
serg [7]

Complete question is;

Roger and Rita each drive at a constant speed between Phoenix and San Diego. Each driver’s distance for the same section of the trip is displayed below. Who had a head start, and how many miles was the head start?

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B) Roger had a 26-mile head start.

C) Roger had a 25-mile head start.

D) Rita had a 22-mile head start.

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A) Rita had a 28-mile head start.

Step-by-step explanation:

Let's assume that Roger travelled a distance of 60 miles

And that;

Rita travelled a distance of 32 miles

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Thus, it means that Rita had a head start of Roger since she covered only 32 miles.

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What digit could be in the ten millions place of a number that is greater than 25 million but less than 73 million
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For the answer to the question above, 
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<span>1 + nx + [n(n-1)/(2 x 1)](x)^2 + [n(n-1)(n-2)/3 x 2 x 1] (x)^3 </span>

<span>1 + nx + [n(n-1)/2](x)^2 + [n(n-1)(n-2)/6] (x)^3 </span>

<span>1 + 9x + 36x^2 + 84x^3 </span>

<span>In my experience, up to the x^3 is often adequate to approximate a route. </span>

<span>(1+x) = 0.98 </span>

<span>x = 0.98 - 1 = -0.02 </span>

<span>Substituting: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 </span>

<span>approximation = 0.834 </span>

<span>Checking the real value in your calculator: </span>

<span>(0.98)^9 = 0.834 </span>

<span>So you have approximated correctly. </span>

<span>If you want to know how accurate your approximation is, write out the result of each in full: </span>

<span>1 + 9(-0.02) + 36(-0.02)^2 + 84(-0.02)^3 = 0.833728 </span>

<span> (0.98)^9 = 0.8337477621 </span>

<span>So it is correct to 4</span>
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