Answer:
1 and 2
Step-by-step explanation:
I hope this helps you out!
<em>⇨ Use the formula below</em>
<em />
<em>⇨ Substitute the parameters:</em>
<em />
<em />
Hope that helped
Total cost=$142
cost of parts=$62
cost paid for labour=$142-$62=$80
According to question,
》cost of labour per hr=$32
which can be written as,
》cost of labour/time=$32
Use cross multiplication,
》time=cost of labour/32
Since cost of labour is 80,
Time=80/32
=2.5hrs
<h2><em>y
2
+
6
y
−
16
=
(
y
+
8
)
(
y
−
2
)
</em></h2><h2 /><h2><em>Explanation:
</em></h2><h2><em>Note that in general:
</em></h2><h2 /><h2><em>(
y
+
a
)
(y
−
b
)
=
y
2
+
(
a
−
b
)
y
−
a
b
</em></h2><h2 /><h2><em>So we want to find a pair of factors a and b of 16 which differ by 6
. </em></h2><h2><em>The pair 8
,
2 works in that 8−
2
=
6 and 8
⋅
2=
16
.
</em></h2><h2 /><h2><em>Hence:
</em></h2><h2><em>
y
2
+
6
y
−
16
=
(
y+
8
)
(
y
−
2
)</em></h2><h2><em>y=2,-8</em></h2>
