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3 years ago

Which phrase matches the expression c^3

Mathematics

1 answer:

Yuliya22 [10]3 years ago

4 0

Answer:A

Step-by-step explanation:

Think about it as a process of elimination.

It can't be "B' for the simple fact that "increased by'' is a term that is often used for addition problems.

It can't be "C" because, as previously stated, sum is a term that is used in addition problems.

It can't be "D" because this is a unit that you are using.

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Adriana worked 38 hours last week. Her job pays $12 an hour. How much did she earn last week?

rusak2 [61]

Multiply the hours by how much she makes per hour.

38 * 12 = $456

Therefore, she made $456 last week.

Best of Luck!

5 0

3 years ago

Help please need to be done ASAP

storchak [24]

Answer: 16, 3, 9, 80

5 0

3 years ago

Find the value of x. 3x(5+2)=16

Iteru [2.4K]

Answer:

16/21

Step-by-step explanation:

We are given the equation 3x(5 + 2) = 16.

By order of operations, let's add the two numbers in the parentheses first:

3x(5 + 2) = 16

3x(7) = 16

Now, we must multiply 3x by 7:

3x * 7 = 16

21x = 16

Divide both sides by 21:

x = 16/21

The answer is thus 16/21.

~ an aesthetics lover

8 0

3 years ago

Read 2 more answers

A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it

natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, $h_o=5\ ft$

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

$h=-16t^2+vt+h_0$

Putting all the values,

$h=-16t^2+60t+5$ .....(1)

For maximum height, put

$\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s$

Put t = 1.875 in equation (1)

$h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m$

So, the maximum height reached by the ball is 61.25 m.

8 0

3 years ago

Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day. If Mr.Mason drinks 118 ounces

denis-greek [22]

The total weight of Mason is 177

Solution:

Given that, Mr.Mason takes two-thirds of his body weight and drinks that amount of gatorade in ounces per day

Mr.Mason drinks 118 ounces each day

Let "x" be the total weight of Mr.Mason

Therefore, we can say,

Two third of body weight = Amount of gatorade drank in ounces per day

Two third of x = 118

$\frac{2}{3} \text{ of } = 118\\\\\frac{2}{3} \times x = 118\\\\2x = 118 \times 3\\\\2x = 354\\\\x = \frac{354}{2}\\\\x = 177$

Thus total weight of Mason is 177

6 0

3 years ago