So 4 hours
1 hour=60 minutes
1 minute=60 seconds
1 hour=60 times 60 seconds=3600seconds
4 hours=3600 seconds times 4=14400seconds
so 8 out of 14400
8/14400=2/3600=1/1800
percent means parts out of100 so
x%=x/100
the reatios are equal to
1/1800=x/100
mulitply both sides by 100
100/1800=x
1/18=x
divide out
0.055555555=x
round
0.06%
Yee
(apologies in advance for foematring. I'm on mobile)
log rules
if no base is stared assume base 10
log_a(b)=c means a^c=b
log(a)+log(b)=log(ab)
if a^b=c^b and b=b then a=c
so
log(2x)+log(x)=2
log_10(2x^2)=2
10^2=2x^2
100=2x^
50=x^2
He had walked 8 blocks, and that was 25% (or .25) of the distance to the school. Let’s let “D” represent the total distance...
D x .25 = 8 blocks
Divide both sides of the equation to solve for D...
D = 8 / .25 = 32
So the total number of blocks to his school is 32.
Answer:
∠3=140°
Step-by-step explanation:
∠4 = 40°
∠3 + ∠4 = 180° (co-exterior angles are equal)
∠3 + 40° = 180°
∠3 = 180° - 40°
∠3 = 140°
∠2 = ∠4 = 40° (corresponding angles)
∠3 + ∠2 = 180° (linear pair)
∠3 + 40° = 180°
∠3 = 180° - 40°
∠3 = 140°
hope you understood
Answer:
Apply sine theorem:
1.
c/sinC = a/sinA
=> sinC = sinA x (c/a) = sin70 x 28/24 = 1.096 => Invalid ( 1.096 > 1)
=> C is undefined
=> B is undefined
2.
c/sinC = b/sinB
=> sinB = sinc x (b/c) = sin40 x 34/33 = 0.662
=> B = arcsin(0.662) = 41.47 deg
3.
c/sinC = b/sinB
=> sinB = sinC x (b/c) = sin29 x 26/6 = 2.101 => Invalid ( 2.101 > 1)
=> B is undefined
=> A is undefined
4.
c/sinC = a/sinA
=> sinC = sinA x (c/a) = sin28 x 20/16 = 0.587
=> C = arcsin(0.587) = 35.93 deg
Hope this helps!
:)