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3 years ago

How to solve???????????

Mathematics

1 answer:

Soloha48 [4]3 years ago

6 0

Answer:

$70.88

Step-by-step explanation:

To find sales tax, multiply the price by the percentage as a decimal.

$67.50 67.50(0.05) = $3.38

Since sales tax is 5%, its decimal equivalent is 0.05 and for the price of $67.50 you pay $3.38.

The total amount paid is the price added to the sales tax.

$67.50 + 3.38 = $70.88

Repeat these steps for each price in the sales amount column.

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Write 931 x 10-5 in standard notation.

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3 years ago

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A bowl contains 4 red marbles and 3 yellow marbles. Tim randomly draws 3 red marbles from the bowl. He replaces each marble afte

mr Goodwill [35]

So,

The probability of drawing a yellow marble is $\frac{3}{7}$ .
Since he replaces the marble after it is drawn out, the probability of drawing another yellow is the same: $\frac{3}{7}$ .

The probability of drawing a red marble is $\frac{4}{7}$ .

In order to get the probability of drawing 2 yellow marbles and 1 red marble, given that each marble is replaced after it is drawn out, we must multiply the fractions together.

$( \frac{3}{7} )( \frac{3}{7} )( \frac{4}{7} ) = \frac{36}{343}$

Because the order of the marbles doesn't matter, we will multiply the probability by 3.
$3( \frac{36}{343} ) = \frac{108}{343}$

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2 years ago

Help please solve<br> <img src="https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B6x%5E5%2B11x%5E4-11x-6%7D%7B%282x%5E2-3x%2B1

Shkiper50 [21]

Answer:

$\displaystyle -\frac{1}{2} \leq x < 1$

Step-by-step explanation:

<u>Inequalities</u>

They relate one or more variables with comparison operators other than the equality.

We must find the set of values for x that make the expression stand

$\displaystyle \frac{6x^5+11x^4-11x-6}{(2x^2-3x+1)^2} \leq 0$

The roots of numerator can be found by trial and error. The only real roots are x=1 and x=-1/2.

The roots of the denominator are easy to find since it's a second-degree polynomial: x=1, x=1/2. Hence, the given expression can be factored as

$\displaystyle \frac{(x-1)(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)^2(x-\frac{1}{2})^2} \leq 0$

Simplifying by x-1 and taking x=1 out of the possible solutions:

$\displaystyle \frac{(x+\frac{1}{2})(6x^3+14x^2+10x+12)}{(x-1)(x-\frac{1}{2})^2} \leq 0$

We need to find the values of x that make the expression less or equal to 0, i.e. negative or zero. The expressions

$(6x^3+14x^2+10x+12)$

is always positive and doesn't affect the result. It can be neglected. The expression

$(x-\frac{1}{2})^2$

can be 0 or positive. We exclude the value x=1/2 from the solution and neglect the expression as being always positive. This leads to analyze the remaining expression

$\displaystyle \frac{(x+\frac{1}{2})}{(x-1)} \leq 0$