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erma4kov [3.2K]
3 years ago
8

PLEASE HELP ANYONE!!!

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
8 0

Option D : 180.5 \ in^2 is the area of the kite.

Explanation:

The formula to find the area of the kite is given by

A=\frac{1}{2} d_{1} d_{2}

where d_1 and d_2 are the diagonals of the kite.

From the figure, we can determine the lengths of the diagonals d_1 and d_2

The length of the diagonal d_1 is

d_1=7 \ in +12 \ in\\d_1=19 \ in

The length of the diagonal d_2 is

d_2=9.5 \ in+9.5 \ in\\d_2=19 \ in

Thus, the lengths of the diagonals d_1 and d_2 are 19 \ in and 19 \ in respectively.

Substituting these values in the formula A=\frac{1}{2} d_{1} d_{2}, we get,

A=\frac{1}{2} (19\times19)

A=\frac{1}{2} (361)

A=180.5 \ in^2

Thus, the area of the kite is 180.5 \ in^2

Hence, Option D is the correct answer.

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Back side lateral area and surface area
stepan [7]
<h2>7. Find the lateral and surface area.</h2>

This is a regular pyramid. A regular pyramid is a right pyramid whose base is a regular polygon and whose apex is directly above the centre of the base. The lateral surface area is the sum of the areas of all the lateral faces while  the surface area is the sum of all the lateral faces plus its base. In this exercise, the base is a square so this is also a square pyramid. Next, we have:

LATERAL SURFACE AREA:

For the lateral sides, we have four identical triangles, so the area of a triangle can be found as:

A=\frac{bh}{2} \\ \\ Where: \\ \\ b:base \\ \\ h:height

and the lateral surface will be four times this value:

S_{L}=4A

The base of the triangle is the same as the base of the square. So:

b=9yd.

On the other hand, the height of the triangle is the slant height of the pyramid, which is:

h=10yd

So the area of a triangle is:

A=\frac{(9)(10)}{2} \\ \\ A=45yd^2

Therefore:

S_{L}=4(45)\\ \\ \boxed{S_{L}=180yd^2}

SURFACE AREA:

The surface area can be found as:

S=S_{L}+A_{b} \\ \\ Where: \\ \\ A_{b}: Area \ of \ the \ base \\ \\ S_{L}: Lateral \ surface

Calculating the area of the base, which is a square, we have:

A_{b}=b^2 \\ \\ A_{b}=9^2 \\ \\ A_{b}=81yd^2

Therefore:

S=180+81 \\ \\ \boxed{261yd^2}

<h2>8. Find the lateral and surface area.</h2>

In this case, we have another similar pyramid compared to the previous one, but we are given the height of the pyramid and we'll name it H in capital letter. We know that the area of a triangle is:

A=\frac{bh}{2} \\ \\ Where: \\ \\ b:base \\ \\ h:height

and the lateral surface will be:

S_{L}=4A

To find h, which is the slant height of the pyramid, we need to use the Pythagorean theorem. Next, it is true that:

h=\sqrt{\left(\frac{b}{2}\right)^2+H^2} \\ \\ b=14 \\ H=12 \\ \\ h=\sqrt{\left(\frac{14}{2}\right)^2+12^2} \therefore h=\sqrt{193}

So the area of a triangle is:

A=\frac{(14)(\sqrt{193})}{2} \\ \\ A=7\sqrt{193}ft^2

Therefore:

S_{L}=4(7\sqrt{193})\\ \\ S_{L}=28\sqrt{193}ft^2 \approx 388.9884

Rounding to the nearest tenth:

\boxed{S_{L}=389.0ft^2}

SURFACE AREA:

We know that the surface area can be found as:

S=S_{L}+A_{b} \\ \\ Where: \\ \\ A_{b}: Area \ of \ the \ base \\ \\ S_{L}: Lateral \ surface

Calculating the area of the base, which is a square, we have:

A_{b}=b^2 \\ \\ A_{b}=14^2 \\ \\ A_{b}=196ft^2

Therefore:

S=28\sqrt{193}+196 \\ \\ S \approx 584.9884ft^2

Rounding to the nearest tenth:

\boxed{S=585ft^2}

<h2>9. Lateral surface area.</h2>

Here Patrick is making a paper model of castle. He has a net, so he can fold it to build up a pyramid. That's amazing, right? Well, recall that for a pyramid  like that the lateral surface area is the area of the lateral faces, that are all triangles. Thus, for a triangle:

A=\frac{bh}{2} \\ \\ Where: \\ \\ h: \ slant \ height \ of \ the \ pyramid \\ \\ b: base \ of \ the \ pyramid

The slant height of the pyramid is h=20cm because this is the same height of the triangle. On the other hand, the base is b=15cm. So:

A=\frac{15(20)}{2} \\ \\ h=150cm^2

Next the lateral surface area is:

S_{L}=4(150) \\ \\ \boxed{S_{L}=150cm^2}

________________

<h2>THE OTHER ANSWERS HAVE BEEN ATTACHED BELOW.</h2>
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Step-by-step explanation:

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