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ipn [44]
3 years ago
11

Write the expression in standard form. (6f-5+3g)-(-6g+3)

Mathematics
1 answer:
andreev551 [17]3 years ago
6 0
(6f-5+3g)-(-6g+3) = <span>6f-5+3g-(-6g)-3) = 6f-8+3g+6g = 6f+9g-8.</span>
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A=1/2 bh (base/height)<br> =.5(12)4<br> a=24ft<br> how did i get the answer a=24?
vampirchik [111]
That’s what i got
step by step explanation
4 0
3 years ago
a country's population in 1992 was 169 million in 1999 it was 174 million estimate the population in 2010 using the exponential
ahrayia [7]
In 1992: t=0 and A=169 million
In 1999: t=7 and P= 174 million

Solve for k: blah blah blah

In 2010: t=18

The answer is : 182 million (trust me)
7 0
3 years ago
Marine fuel is a combination of gasoline and motor oil. The standard gasoline and oil mixture is about 98% gasoline and about 2%
Georgia [21]

Answer:

0.98g+ 0.02m= 7.1224 gallons standard mixture

0.96g+ 0.04m= 6.25 gallons break oil

3.92 gallons of gasoline  is required for  4 gallons the standard mixture

Step-by-step explanation:

If we have to use 6 gallons of gasoline this means that 98%= 6 gallons and 2% would be 6/98*2

Gasoline: Motor oil

6              :    x

98        : 2

Using the product rule

x= 6*2/98= 0.1224 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the standard oil the equation would be

0.98g+ 0.02m= 7.1224 gallons standard mixture

For break in oil

Gasoline: Motor oil

6              :    x

96        : 4

Using the product rule

x= 6*4/96= 0.25 gallons of motor oil is required.

Let the gasoline be represented by g and motor oil by m then for the break oil the equation would be

0.96g+ 0.04m= 6.25 gallons break oil

Part b. For  4 gallons of the "break in" mixture

96% of the 4 gallons of the "break in" mixture is gasoline =  3.84 gallons of gasoline

4% of 4 = 0.16 gallons of motor oil

Now the standard mixture 4 gallons would contain 98 % of gasoline and 2 % of motor oil

98% of 4 gallons= 3.92 gallons of gasoline

2% of  4 gallons= 0.08 gallons of motor oil.

6 0
3 years ago
Cylinder E has the following dimensions: h = 30 cm and r = 4 cm. Cylinder F has the same radius, but has a height of 5 cm . What
Anarel [89]

Answer:

1759.52cm^3

Step-by-step explanation:

Given data

Cylinder E

h = 30 cm and

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*30

V= 3.142*16*30

V=1508.16 cm^3

Cylinder F

h=5 cm

r = 4 cm

The expression for the volume is

V= πr^2h

V= 3.142*4^2*5

V= 3.142*16*5

V=251.36 cm^3

Hence the total volume is

=251.36+1508.16

= 1759.52cm^3

6 0
3 years ago
Two runners start at the same point;Jayne and Jared.
Tomtit [17]

Answer:

160

Step-by-step explanation:

  1. 8
  2. 16
  3. 24
  4. 32
  5. 40
  6. 48
  7. 56
  8. 64
  9. 72
  10. 80
  11. 88
  12. 96
  13. 104
  14. 112
  15. 120
  16. 128
  17. 136
  18. 144
  19. 152
  20. 160
6 0
3 years ago
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