3 years ago

HELP!! please I can't figure this out

Mathematics

1 answer:

Fofino [41]3 years ago

7 0

12.875 pounds is the answer

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Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc

In-s [12.5K]

Answer:

$\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

$L^2 = y^2 + x^2$

$\implies L = \sqrt{y^2 + x^2}$ ,

Differentiating with respect to time (t),

$\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})$

$=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)$

$=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})$

$=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})$

Here,

$\frac{dy}{dt}=-6\text{ ft per sec}$

Also, $\frac{dL}{dt} = 0$ ( Ladder length = constant ),

$\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0$

$-6x + y\frac{dy}{dt}=0$

$y\frac{dy}{dt}=6x$

$\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}$

Which is the required notation.

8 0

3 years ago

Use the distributive property to find the product

dalvyx [7]

Answer:

1st one: -24a-6b-36c

2nd one: 14mn-12m

Step-by-step explanation:

1st one: Multiply '-6' w/ '4a', 'b', and '6c'

2nd one: Multiply '2m' w/ '7n' and '-6'

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You have $40 in your wallet, but you do not want to spend all of it. You want to have at least some money left. You find a shirt

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Answer:

Step-by-step explanation:

40-5=35

35 is left over so it is yout leftover change or money

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(0,8)

Step-by-step explanation:

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this is hard what grade is this for

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HELP!! please I can't figure this out​

HELP!! please I can't figure this out