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alekssr [168]
3 years ago
8

Atherine has $54. She plans to spend more than $20 of the money for a painting canvas. The rest will go toward paints. Each tube

of paint costs $8.50. Assume that x represents the number of tubes of paint Catherine can buy.
Mathematics
1 answer:
horsena [70]3 years ago
4 0

I think that she could buy 3 tubes of paint because that's $25.50 and that gives you 28.50 for the canvas.

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bet

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Five of every six gifts were wrapped in blue paper. If there are 25 gifts wrapped in blue paper, how many gifts are there altoge
melamori03 [73]

Answer:

There are 30 gifts altogether.

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3 years ago
Find the percent of this number: 32% of 25 pages<br><br> Would it be 8% or 32%?
GuDViN [60]
32% * 25 =
(32*25)/100
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8%
5 0
3 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 30,393 miles, with a standard
Pie

Answer:

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem:

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 30393, \sigma = 2876, n = 37, s = \frac{2876}{\sqrt{37}} = 472.81

What is the probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

This probability is the pvalue of Z when X = 30393 + 339 = 30732 subtracted by the pvalue of Z when X = 30393 - 339 = 30054. So

X = 30732

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{30732 - 30393}{472.81}

Z = 0.72

Z = 0.72 has a pvalue of 0.7642.

X = 30054

Z = \frac{X - \mu}{s}

Z = \frac{30054 - 30393}{472.81}

Z = -0.72

Z = -0.72 has a pvalue of 0.2358

0.7642 - 0.2358 = 0.5284

52.84% probability that the sample mean would differ from the population mean by less than 339 miles in a sample of 37 tires if the manager is correct

4 0
3 years ago
Estimate the solution of the system x+y=4 2x-y=6 by sketching a graph of each linear function. Then solve the system algebraical
Juli2301 [7.4K]

Answer:

(10/3, 2/3)

Step-by-step explanation:

You may find it easier to write these two equations x+y=4 2x-y=6 in a column:

x+y=4

2x-y=6

Adding these together will eliminate y:

3x = 10.  Then x = 10/3.

Substituting 10/3 for x in the first equation results in:

10/3 + y = 4

Clear fractions by multiplying all three terms by 3:

10 + 3y = 12

Then 3y = 2, and y = 2/3.

The solution is (10/3, 2/3)

8 0
3 years ago
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