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3 years ago

If m angle N = (5x)° and m angle L = (x + 20)°, what is the value of x?

Mathematics

2 answers:

Fynjy0 [20]3 years ago

8 0

Hello there.

<span>If m angle N = (5x)° and m angle L = (x + 20)°, what is the value of x?

</span>b. 5

monitta3 years ago

6 0

We can't tell. We need to know how the angles N and L are related.

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-2/7x=4/7 how to check your answer

Ymorist [56]

Answer:

1)Evaluate the left-hand side expression at the given value to get a number.

2)Evaluate the right-hand side expression at the given value to get a number.

3)See if the numbers match.

Sorry if wrong

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3 years ago

Solve each prportion. (2/y-4)=(y+3/4)

vampirchik [111]

Answer:

y = 5, -4

Step-by-step explanation:

To solve proportions you cross-multiply.

$\frac{2}{y-4} =\frac{y+3}{4} \rightarrow 2\times4 = (y-4)\times(y+3) \rightarrow 8=y^2-y-12$

Now that we have 8 = y^2 - y - 12, we must make the entire trinomial equal to 0 by subtracting 8 from both sides.

y^2 - y - 20 = 0

Factor the trinomial.

(y - 5)(y + 4) = 0

Make both factors equal to 0 to solve for both values of y.

y - 5 = 0 --> y = 5
y + 4 = 0 --> y = -4

y = 5, -4

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3 years ago

Henrietta is mixing paint for an art project. She uses 2 cups of red paint for every 3 cups of yellow paint for each batch. If s

bezimeni [28]

2/3=6/x
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2 years ago

I just need 30 please

PIT_PIT [208]

In the smaller triangle, let $y$ be the length of the smallest leg. Then the smallest leg in the larger triangle is $14-y$ .

Within the scope of the smaller triangle, we have $y$ such that

$x^2+y^2=13^2\implies y=\sqrt{13^2-x^2}$

Then within the larger the triangle, we would have

$x^2+(14-y)^2=15^2\iff x^2+\left(14-\sqrt{13^2-x^2}\right)^2=15^2$

Now we can solve for $x$ :

$x^2+14^2-28\sqrt{13^2-x^2}+(13^2-x^2)=15^2$

$\implies x=12$

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3 years ago

How do you estimate 586-321

aniked [119]

I would estimate about 240

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3 years ago

Read 2 more answers