The waiting time at which 10 percent of the people would continue to hold is given as 2.3
<h3>How to solve for the waiting time</h3>
We have to solve for X ~ Exponential(λ).
then E(X) = 1/λ = 3,
= 0.3333
Remember that the cumulative distribution function of X is F(x) = 1 - e^(-λx). ; x is equal to the time in over case
For 10 percent of the people we would have a probability of
10/100 = 0.1
we are to find
P(X ≤ t)
= 1 - e^(0.3333)(t) = 0.1
Our concern is the value of t
Then we take the like terms
1-0.1 = e^(0.3333)(t)
1/0.9 = e^(0.3333)(t)
t = 3 * ln(1/0.9)
= 0.3157
The goal in order to identify if the task are performed in a
poor or good manner and if there are any deficient KSAO’s in the workforce is
known as the task analysis. This is a process about having to use observation
as a way of having to understand tasks or details that are being performed and
if the goal has been reach.
Answer:
D. $ 10,300
Choice D is correct: Net income = $ 10,300
Explanation:
Cash Received = $ 16000
Less Rent Paid= ( $ 2000)
Add income = $ 3000
Less Salaries for the month of March = ($ 6200)
Less utilities paid ($ <u>500)</u>
<u>Net income=</u> $ 10,300
Treatments.
Net income is found by deducting expenses from revenues earned
$ 100,000 is the retained earnings so it is not accounted for net income.
Equipment is an asset so it is not accounted for net income.
Cash received is the revenue so it is accounted.
Rent is an expense account so it is subtracted.
Income for service $ 3000 provided is also taken into account on matching principle basis.
Advance received will be adjusted when the services will be rendered on matching principle.
