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3 years ago

Simplify each expression. 3a^2b^-4/12a^-2b^-2, a=0, b=0

Mathematics

2 answers:

Liula [17]3 years ago

4 0

Answer:

The answer is A on Edg. a^4/4b^2

For the second one its B -v^9/w^6

Step-by-step explanation:

Maksim231197 [3]3 years ago

3 0

Answer:

The answer is that 36a⁴/b² is 0.

Step-by-step explanation:

Let's simplify the expression given to us, this way:

3a^2b^-4/12a^-2b^-2

3a²b⁻⁴ ÷ 12a⁻²b⁻²

3a²/b⁴ ÷ 1/12a²b²

3a²/b⁴ * 12a²b²/1

36a⁴/b²

But let's recall that if a = 0 and b = 0, then we have:

36 * 0⁴ / 0² = 0

The answer is that 36a⁴/b² is 0.

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kozerog [31]

Answer:

$x=3$

Step-by-step explanation:

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3 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

In a cricket match, Rajat scored thrice as many runs as Devansh.

Rina8888 [55]

Answer:

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Step-by-step explanation:

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3 years ago

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An equation of the perpendicular bisector of the line segment with end points (3,0) and (-3,0) is

Norma-Jean [14]

Answer:

$x = 0$

Step-by-step explanation:

Given

$(x_1,y_1) = (3,0)$

$(x_2,y_2) = (-3,0)$

Required

The equation of the perpendicular bisector.

First, calculate the midpoint of the given endpoints

$(x,y) = 0.5(x_1 + x_2, y_1 + y_2)$

$(x,y) = 0.5(3-3, 0+ 0)$

$(x,y) = 0.5(0, 0)$

Open bracket

$(x,y) = (0.5*0, 0.5*0)$

$(x,y) = (0, 0)$

Next, determine the slope of the given endpoints.

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$m = \frac{0 - 0}{-3- 3}$

$m = \frac{0}{-6}$

$m = 0$

Next, calculate the slope of the perpendicular bisector.

When two lines are perpendicular, the relationship between them is:

$m_2 = -\frac{1}{m_1}$

In this case:

$m = m_1 = 0$

So:

$m_2 = -\frac{1}{0}$

$m_2 = unde\ fined$

Since the slope is $unde\ fined$ , the equation is:

$x = a$

Where:

$(x,y) = (a,b)$

Recall that:

$(x,y) = (0, 0)$

So:

$a = 0$

Hence, the equation is:

$x = 0$

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

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