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grin007 [14]
3 years ago
15

Solve for x in the equation x2-8x+41=0

Mathematics
1 answer:
Zinaida [17]3 years ago
6 0
x^2-8x+41=0\ \ \ \ |-41\\\\x^2-2\cdot x\cdot4=-41\ \ \ \ |+4^2\\\\\underbrace{x^2-2\cdot x\cdot4+4^2}_{(a-b)^2=a^2-2ab+b^2}=-41+4^2\\\\(x-4)^2=-41+16\\\\(x-4)^2=-25 < 0

Answer: No real solutions

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