Answer:
30.17feet high
Step-by-step explanation:
Given the following
the distance from the base of the pole to the tip of the shadow = 49feet (hypotenuse)
angle of elevation = 38°
Required
Height of the flagpole (opposite)
Using the SOH CAH TOA identity
Sin theta = opposite/hypotenuse
Sin 38 = H/49
H = 49sin38
H = 49(0.6157)
H = 30.17feet
Hence the flagpole is 30.17feet high
The 5 ft. and 3 in. total to 63 in. So, you take away 5 in. from 63 in. and your total would be 58 in. (4 ft. 10 in.)
Answer: 58 inches or 4 feet 10 inches
Credit to: @Emanuel9
even when you don't see it,
God's working : )
Simplifying <span>4y + -70 = 12y + 2
</span>
Add -12y to each side of the equation. -70 + 4y + -12y = 2 + 12y + -12y
<span>Add 70 to each side of the equation.
-70 + 70 + -8y = 2 + 70
</span>
Divide each side by -8.
<span>
</span>So y = -9 is your answer.
Hope I Helped!!!
Divide 54 by 3 which will get you q=18
Answer:
here:
1. -9
2. -28
3. 54
4. -100
5. -60
6. -0
7. 49
8. -135
9. -96
10. 300
11. -153
12. -192
THIS TOOK LONG BECAUSE I DID A LONG ONE BUT THEN I MADE IT SHORTER. :D
