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Reil [10]
4 years ago
12

Jay is running 6 miles. He has run

Mathematics
2 answers:
Tems11 [23]4 years ago
5 0

Answer:

the answer is C ,

Step-by-step explanation:

SVEN [57.7K]4 years ago
4 0

Answer:

It's C) 7,040 yards.


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Airplane is flying at 9000 feet.It begins descending at a rate of 500 feet per minutes write an equation
Hunter-Best [27]

Answer:

9000 - 500m

Step-by-step explanation:

Your original number is 9000. It starts to decrease at a rate of 500 feet per minute. So we know that you will subtract 500 from 9000 but we don't know how many times. Because of this, we will put a variable to represent the minutes that we are descending.

In conclusion: 9000 - 500m

7 0
4 years ago
If a = 12 and B = 43 degrees, find c.
ludmilkaskok [199]

Answer:

74

Step-by-step explanation:

You subtract 43 from 12 you get 31 then you add 43 and 31 you get 74 bye

8 0
4 years ago
Read 2 more answers
A certain freely falling object, released from rest, requires 1.50 s to travel the last 30.0 m before it hit the ground. a.Find
Lyrx [107]
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2 
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
4 0
4 years ago
-12 + 8a = -a + 6(2a - 2)
pogonyaev

Answer:

41/6

Step-by-step explanation:

-12+81=-1+6(2a-2)

first distribute:

-12+81=-1+12a-12

combine like terms:

<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>

69=-13+12a

add -13 with 69:

82=12a

divide 82 and 12:

82/12= 41/6

3 0
3 years ago
Read 2 more answers
Evaluate the piecewise function at the given values of the independent variable
snow_lady [41]
A) For f(-1) we use the part of the piecewise function for when x < 0 because -1 < 0. Plug in -1 for x:

2(-1) + 3 = 1

b) For f(0), we use the part for when x \geq 0.

4(0) + 5 = 5

c) For f(2) we use the part for when x \geq 0.

4(2) + 5 = 13
3 0
3 years ago
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