Answer:
9000 - 500m
Step-by-step explanation:
Your original number is 9000. It starts to decrease at a rate of 500 feet per minute. So we know that you will subtract 500 from 9000 but we don't know how many times. Because of this, we will put a variable to represent the minutes that we are descending.
In conclusion: 9000 - 500m
Answer:
74
Step-by-step explanation:
You subtract 43 from 12 you get 31 then you add 43 and 31 you get 74 bye
A.)
<span>s= 30m
u = ? ( initial velocity of the object )
a = 9.81 m/s^2 ( accn of free fall )
t = 1.5 s
s = ut + 1/2 at^2
\[u = \frac{ S - 1/2 a t^2 }{ t }\]
\[u = \frac{ 30 - ( 0.5 \times 9.81 \times 1.5^2) }{ 1.5 } \]
\[u = 12.6 m/s\]
</span>
b.)
<span>s = ut + 1/2 a t^2
u = 0 ,
s = 1/2 a t^2
\[s = \frac{ 1 }{ 2 } \times a \times t ^{2}\]
\[s = \frac{ 1 }{ 2 } \times 9.81 \times \left( \frac{ 12.6 }{ 9.81 } \right)^{2}\]
\[s = 8.0917...\]
\[therfore total distance = 8.0917 + 30 = 38.0917.. = 38.1 m \] </span>
Answer:
41/6
Step-by-step explanation:
-12+81=-1+6(2a-2)
first distribute:
-12+81=-1+12a-12
combine like terms:
<u>-12+81</u>= <u>-1</u>+12a<u>-12</u>
69=-13+12a
add -13 with 69:
82=12a
divide 82 and 12:
82/12= 41/6
A) For f(-1) we use the part of the piecewise function for when x < 0 because -1 < 0. Plug in -1 for x:
2(-1) + 3 = 1
b) For f(0), we use the part for when x
0.
4(0) + 5 = 5
c) For f(2) we use the part for when x
0.
4(2) + 5 = 13
