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Effectus [21]
3 years ago
5

Help wanted pls math

Mathematics
2 answers:
Serjik [45]3 years ago
3 0

Answer:

39 ft²

Step-by-step explanation:

Area of a triangle = 1/2bh

Let:

base = b = 4 ft

height = h = 3 ft

Solve for the area of the triangle:

A = 1/2(4)(3)

A = 2 * 3

A = 6 ft²

Area of a rectangle = bh

Let:

base = b = 9 ft

height = h = 5 ft

Solve for the area of the rectangle:

A = (9)(5)

A = 9 * 5

A = 45 ft²

Subtract the area of the triangle from the area of the rectangle:

45 - 6 = 39 ft²

39 ft² is your answer.

~

Alexxx [7]3 years ago
3 0

Answer:

39 ft²

Step-by-step explanation:

Shaded area = rectangle - triangle

(5 × 9) - (½ × 3 × 4)

45 - 6

39 ft²

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2 years ago
In ΔRST, t = 4.1 inches, r = 7.1 inches and ∠S=45°. Find the length of s, to the nearest 10th of an inch.
dem82 [27]

Answer:

The length of s is 5.1 inches to the nearest tenth of an inch

Step-by-step explanation:

In Δ RST

∵ t is the opposite side to ∠T

∵ r is the opposite side to ∠R

∵ s is the opposite side to ∠S

→ To find s let us use the cosine rule

∴ s² = t² + r² - 2 × t × r × cos∠S

∵ t = 4.1 inches, r = 7.1 inches, and m∠S = 45°

→ Substitute them in the rule above

∴ s² = (4.1)² + (7.1)² - 2 × 4.1 × 7.1 × cos(45°)

∴ s² = 16.81 + 50.41 - 41.1677568

∴ s² = 26.0522432

→ Take √ for both sides

∴ s = 5.10413981

→ Round it to the nearest tenth

∴ s = 5.1 inches

∴ The length of s is 5.1 inches to the nearest tenth of an inch

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