Answer:
The perimeter of the figure is 
Step-by-step explanation:
we know that
The perimeter of the figure is equal to the perimeter of a rectangle plus the circumference of a semicircle minus the diameter of the circle
so
<u>Find the perimeter of the rectangle</u>
The perimeter of the rectangle is equal to

substitute the values

<u>Find the circumference of a semicircle</u>
The circumference of a semicircle is equal to

substitute the value of r
-----> the radius is half the diameter

<u>Find the perimeter of the figure</u>
