Question

This figure consists of a rectangle and semicircle. What is the perimeter of this figure? Use 3.14 for pi. 60.84 m 72.84 m 79.68 m 98.52 m A shape made up of a rectangle of the left and a semicircle on the right. The rectangle has a width of 15 meters and a height of 12 meters.

Answer 1

60.84 (A)
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Answer 2

Answer:

The perimeter of the figure is $60.84\ m$

Step-by-step explanation:

we know that

The perimeter of the figure is equal to the perimeter of a rectangle plus the circumference of a semicircle minus the diameter of the circle

so

Find the perimeter of the rectangle

The perimeter of the rectangle is equal to

$P=2(L+W)$

substitute the values

$P=2(15+12)=54\ m$

Find the circumference of a semicircle

The circumference of a semicircle is equal to

$C=\pi r$

substitute the value of r

$r=12/2=6\ m$ -----> the radius is half the diameter

$C=(3.14)(6)=18.84\ m$

Find the perimeter of the figure

$54\ m+18.84\ m-12\ m=60.84\ m$