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Lera25 [3.4K]
3 years ago
7

If 60 lbs of force must be applied to the valve for it to open, how much upward force must push rod X apply for the valve to ope

n?
Mathematics
1 answer:
bixtya [17]3 years ago
3 0

Answer:

It must push 40 lbs of force to open the valve.

Step-by-step explanation:

The momentum at one end of the pivot must be equal to the momentum at the other end. Assuming the 60 lbs of force (F1) is applied at 2 inches from the pivot (d1) and the upward force (F2) is applied at 3 inches from the pivot (d2), then:

F1*d1 = F2*d2

Solving for F2 we get:

F2 = F1*d1/d2

F2 = 60*2/3 = 40 lbs of force

plz mark me as brainliest :)

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Obtuse is to more than 90° as reflex is to​
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Answer:

  >180° (more than 180°)

Step-by-step explanation:

Angles are classified as ...

  • acute: < 90°
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  • straight/linear: = 180°
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It seems that we're looking at definitions:

  obtuse : >90° :: reflex : >180°

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Can two numbers have the same absolute value
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His conduct at the state dinner was a cavalcade
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(C) "gaffe"

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8 0
1 year ago
The amount of time all students in a very large undergraduate statistics course take to complete an examination is distributed c
Anestetic [448]

Answer:

a) The mean is \mu = 60

b) The standard deviation is \sigma = 9

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The probability a student selected at random takes at least 55.50 minutes to complete the examination equals 0.6915.

This means that when X = 55.5, Z has a pvalue of 1 - 0.6915 = 0.3085. This means that when X = 55.5, Z = -0.5

So

Z = \frac{X - \mu}{\sigma}

-0.5 = \frac{55.5 - \mu}{\sigma}

-0.5\sigma = 55.5 - \mu

\mu = 55.5 + 0.5\sigma

The probability a student selected at random takes no more than 71.52 minutes to complete the examination equals 0.8997.

This means that when X = 71.52, Z has a pvalue of 0.8997. This means that when X = 71.52, Z = 1.28

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Z = \frac{X - \mu}{\sigma}

1.28 = \frac{71.52 - \mu}{\sigma}

1.28\sigma = 71.52 - \mu

\mu = 71.52 - 1.28\sigma

Since we also have that \mu = 55.5 + 0.5\sigma

55.5 + 0.5\sigma = 71.52 - 1.28\sigma

1.78\sigma = 71.52 - 55.5

\sigma = \frac{(71.52 - 55.5)}{1.78}

\sigma = 9

\mu = 55.5 + 0.5\sigma = 55.5 + 0.5*9 = 55.5 + 4.5 = 60

Question

The mean is \mu = 60

The standard deviation is \sigma = 9

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satela [25.4K]
16 / 4 + 12 ___ 4 + 24/2
4 + 12 ___ 4 + 12
16 __ 16

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