X² + x - 12 / x² - x - 20 ÷ 3x² - 24x + 45 / 12x² - 48x - 60
x² + x - 12 / x² - x - 20 * 12x² - 48x - 60 / 3x² - 24x + 45
<u>(x² + x - 12)(12x² - 48x - 60)</u>
(x² - x - 20)(3x² - 24x + 45)
<span><u>12x^4 - 48x³ - 60x² + 12x³ - 48x² - 60x - 144x² + 576x + 720</u>
</span>3x^4 - 24x³ + 45x² - 3x³ + 24x² - 45x - 60x² + 480x - 900
<span>
<u>12x^4 - 48x³ + 12x³ - 60x² - 48x² - 144x² - 60x + 576x + 720</u></span>
3x^4 - 24x³ - 3x³ + 45x² + 24x² - 60x² - 45x + 480x - 900
<u>12x^4 - 36x³ - 252x² + 516x + 720</u>
3x^4 - 27x³ + 9x² + 435x - 900
<u>12(x^4 - 3x³ - 21x² + 43x + 60) </u>
3(x^4 - 9x³ + 3x² + 145x + 300)
<u>4(</u><span><u>x^4 - 3x³ - 21x² + 43x + 60) </u>
</span><span> (x^4 - 9x³ + 3x² + 145x + 300)</span>
The possible values of x could be -5 and -1 ithink idk
N =9/8
n = 1 1/8
Hope this helpsb☺
30x + 42 = 6(5x + 7) you can understand it now
Correct answer: <span>Dot-and-cross-diagram
</span>
Dot-and-cross diagrams are used to represent covalent bonds. The shared electron from one atom is shown as a dot, while the shared electron from the other atom is shown as a cross.
When drawing dot-and-cross diagrams for covalent bonds, you only need to show the electrons in the highest occupied energy level, as only these are involved.
