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LuckyWell [14K]
3 years ago
6

Whats 109 divided by 27 and then simplify it

Mathematics
1 answer:
ioda3 years ago
8 0

109/27 = 4.037037037

Uncertain on what exactly they want on simplified, here are a couple

Rounded (Hundredth) = 4.04

Rounded (Whole & tenth) = 4

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Convert to quarts: 10 pints
Ad libitum [116K]

Answer:

B

Step-by-step explanation:

Pints and Quarts are measures of volume. The relationship between them is rather simple.

We know 2 pints = 1 Quart

The problem gives us the number of pints and we need to find the number of quarts. From the relationship, we see that "pints divided by 2 will give us quarts"

Given >> 10 pints

Hence, number of quarts would be 10/2 = 5

Hence 10 pints = 5 quarts

Answer choice B is right.

8 0
3 years ago
A statement and portions of the flowchart proof are shown. Which reason should appear in box labeled 1?
larisa [96]

Answer:

Angle Addition Postulate

Step-by-step explanation:

Given:

m\angle UVW=30^{\circ}\\ \\m\angle WVX=75^{\circ}

Prove:

m\angle UVX=105^{\circ}

Proof:

1. m\angle UVX=m\angle UVW+m\angle WVX - Angle Addition Postulate

2. m\angle UVW=30^{\circ} - given

3. m\angle WVX=75^{\circ} - given

4. m\angle UVX=30^{\circ}+75^{\circ} - Substitution Property of Equality

5.  m\angle UVX=105^{\circ} - Simplify

4 0
3 years ago
Tracey paid $165 for an item that was originally priced at $450. What percent of the original price did Tracey pay? Round your p
Ipatiy [6.2K]

Answer:

36.67%

Step-by-step explanation:

To find the percent, divide 165 by 450 (part over whole) and multiply by 100

(165/450) x 100

= 36.67

So, Tracey paid 36.67% of the original price

4 0
2 years ago
X and y are normal random variables with e(x) = 2, v(x) = 5, e(y) = 6, v(y) = 8 and cov(x,y)=2. determine the following: e(3x 2y
andriy [413]

The result for the given normal random variables are as follows;

a. E(3X + 2Y) = 18

b. V(3X + 2Y) = 77

c. P(3X + 2Y < 18) = 0.5

d. P(3X + 2Y < 28) = 0.8729

<h3>What is normal random variables?</h3>

Any normally distributed random variable having mean = 0 and standard deviation = 1 is referred to as a standard normal random variable. The letter Z will always be used to represent it.

Now, according to the question;

The given normal random variables are;

E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8.

Part a.

Consider E(3X + 2Y)

\begin{aligned}E(3 X+2 Y) &=3 E(X)+2 E(Y) \\&=(3) (2)+(2)(6 )\\&=18\end{aligned}

Part b.

Consider V(3X + 2Y)

\begin{aligned}V(3 X+2 Y) &=3^{2} V(X)+2^{2} V(Y) \\&=(9)(5)+(4)(8) \\&=77\end{aligned}

Part c.

Consider P(3X + 2Y < 18)

A normal random variable is also linear combination of two independent normal random variables.

3 X+2 Y \sim N(18,77)

Thus,

P(3 X+2 Y < 18)=0.5

Part d.

Consider P(3X + 2Y < 28)

Z=\frac{(3 X+2 Y-18)}{\sqrt{77}}

\begin{aligned} P(3X + 2Y < 28)&=P\left(\frac{3 X+2 Y-18}{\sqrt{77}} < \frac{28-18}{\sqrt{77}}\right) \\&=P(Z < 1.14) \\&=0.8729\end{aligned}

Therefore, the values for the given normal random variables are found.

To know more about the normal random variables, here

brainly.com/question/23836881

#SPJ4

The correct question is-

X and Y are independent, normal random variables with E(X) = 2, V(X) = 5, E(Y) = 6, and V(Y) = 8. Determine the following:

a. E(3X + 2Y)

b. V(3X + 2Y)

c. P(3X + 2Y < 18)

d. P(3X + 2Y < 28)

8 0
1 year ago
What is the volume of the solid figure below? no fake answers
hram777 [196]

You can seperate the prisms then use the formula l*w*h which for the one on top u get V=20 and for the other one is 48 so 20+48= 68 so the volume of the prism is

(☞゚ヮ゚)☞ 68 ☜(゚ヮ゚☜)

8 0
2 years ago
Read 2 more answers
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