Question

Does anyone seriously know how to do these

Answer 1

Thats simple!
h(x)= $\frac{x^{2}+3x }{4x+27}$
find h(-8)
All we need to do is PLUG IN THE -8
h(-8)= $\frac{(-8)^{2}+3(-8) }{4(-8)+27}$
        =$\frac{64-24}{-32+27}$ (negative²=positive,                                                                                negative×positive=negative)
        =$\frac{40}{-5}$
h(-8)=-8