Question

Find the midpoint of the line segment whose endpoints are (-2, 5) and (6, -9).

Answer 1

We know that when $A=(x_A,y_A)$ and $B=(x_B,y_B)$ the midpoint of the line segment AB is given by:

$M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)$

Here $A=(-2,5)$ and $B=(6,-9)$ so:

$M=\left(\dfrac{x_A+x_B}{2},\dfrac{y_A+y_B}{2}\right)=\left(\dfrac{-2+6}{2},\dfrac{5+(-9)}{2}\right)=\\\\\\=\left(\dfrac{4}{2},\dfrac{5-9}{2}\right)=\left(2,\dfrac{-4}{2}\right)=\boxed{\left(2,-2\right)}$