Question

In a species of birds, blue feathers (B) are incompletely dominant to the gene for white feathers (b). Individuals that are heterozygous (Bb) have blue-tipped feathers. A bird with blue-tipped feathers is crossed with a white bird. What is the percent chance that an offspring will have entirely blue feathers? Show your work in a Punnett square.

Answer 1

Answer:

0%

Explanation:

A bird with blue-tipped feathers (genotype Bb), when crossed with a white bird (genotype bb) can produce offspring with genotypes according to the following Punnett square:

$\begin{array}{ccc}\ \ \ &\ B&b\\\end{array}\\\begin{array}{c}b\\b\\\end{array}\left[\begin{array}{cc}bB&bb\\Bb&bb\\\end{array}\right]$

In other to have entirely blue feathers, an offspring would have to have the BB genotype. Since it is not possible to obtain this genotype by crossing the birds in question,  the percent chance that an offspring will have entirely blue feathers is 0%.