Answer:
Step-by-step explanation:
3 hope this helps :))
A is incorrect and does not represent a function, have a good day
Answer:
![f^{-1}(x) = \frac{cos(2x+6)}{\pi }](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7Bcos%282x%2B6%29%7D%7B%5Cpi%20%7D)
Step-by-step explanation:
![y = \frac{1}{2} cos^{-1} (\pi x)-3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20cos%5E%7B-1%7D%20%28%5Cpi%20x%29-3)
Firstly, we've to interchange the variables.
![x = \frac{1}{2} cos^{-1}(\pi y)-3](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20cos%5E%7B-1%7D%28%5Cpi%20y%29-3)
Solving for y
![x = \frac{cos^{-1} \pi y}{2} -3](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7Bcos%5E%7B-1%7D%20%5Cpi%20y%7D%7B2%7D%20-3)
Adding 3 to both sides
![x+3 = \frac{cos^{-1}(\pi y)}{2}](https://tex.z-dn.net/?f=x%2B3%20%3D%20%5Cfrac%7Bcos%5E%7B-1%7D%28%5Cpi%20y%29%7D%7B2%7D)
Multiplying 2 to both sides
![2(x+3) = cos^{-1} (\pi y)\\2x+6 = cos^{-1} (\pi y)](https://tex.z-dn.net/?f=2%28x%2B3%29%20%3D%20cos%5E%7B-1%7D%20%28%5Cpi%20y%29%5C%5C2x%2B6%20%3D%20cos%5E%7B-1%7D%20%28%5Cpi%20y%29)
Taking cosine on both sides
![\pi y = cos (2x+6)](https://tex.z-dn.net/?f=%5Cpi%20y%20%3D%20cos%20%282x%2B6%29)
Dividing both sides by y
![y = \frac{cos(2x+6)}{\pi }](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7Bcos%282x%2B6%29%7D%7B%5Cpi%20%7D)
Replace y by ![f^{-1}(x)](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29)
=> ![f^{-1}(x) = \frac{cos(2x+6)}{\pi }](https://tex.z-dn.net/?f=f%5E%7B-1%7D%28x%29%20%3D%20%5Cfrac%7Bcos%282x%2B6%29%7D%7B%5Cpi%20%7D)
Since it is in the thousandths place, the value of the six is .006
hope this helps :)
Answer:
Parallel lines have the same slope, so you know the equation will be y = 2x + b. Use the point (1,5) to sub in for (x,y) to solve for b. So, the equation will be y = 2x + 3.
Step-by-step explanation:
hope this help you