Answer:
HEYOOO
The answer must be that it has a MAX
Step-by-step explanation:
Its because the graph has a MAXIMUM "peak" of the line--the maximum point on the graph of which it reaches!
HOPE THIS HELPS!
Answer:
x = 33/5
Step-by-step explanation:
4x+x-15+3-8=13
Combine like terms
5x -20 = 13
Add 20 to each side
5x-20+20 = 13+20
5x =33
Divide by 5
5x/5 = 33/5
x = 33/5
Answer:
Step-by-step explanation:
R(2,3) T(-3,-2) S(2,-2) here are your points.
We can rewrite the expression under the radical as
then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that
since both 
and 
return the same number , and 
captures both possibilities. From here, we have
The absolute values disappear on all but the 
term because all of 
, 
and 
are positive, while 
could potentially be negative. So we end up with
Answer:
See explanation below.
Step-by-step explanation:
Having students in the classroom who are at different levels of knowledge, interest, and ability can be managed by differentiated instruction. This method is a way of thinking that provides a framework where the instructor can set students with learning tasks that are at levels appropriate with the abilities and interests of each student. Each student can have a different type of class and different type of instruction with the differentiated instruction way of thinking.
A gifted and talented student might be assigned a higher math course, perhaps based on a math assessment for advanced placement. Then students that need to stay on the typical high school path of Algebra I, Geometry, Algebra II, and Trigonometry can do that.
Gifted students might take an alternate path with honors classes or trajectories involving Pre-Calculus or advanced placement Calculus, for example. In some instances, universities have allowed High School students to obtain college credit for some courses taken during High School.
Hope this helps! Have an Awesome Day!! :-)
