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quester [9]
3 years ago
9

Michael surveyed 40 of his friends to determine their favorite season. His data shows that 70% said summer, 10% said winter, 5%

said fall, and the rest said spring. What circle graph best represents Michael's data? Circle graph with unequal sections. Sections from smallest to largest are labeled Winter, Spring, Summer, and Fall. The sections for Spring and Summer sections are equal in size. Circle graph with unequal sections. Sections from smallest to largest are labeled Winter, Fall, Summer, and Spring. Circle graph with unequal sections. Sections from smallest to largest are labeled Fall, Winter, Spring, and Summer. Circle graph with unequal sections. Sections from smallest to largest are labeled Fall, Winter, Spring, Summer.

Mathematics
2 answers:
Ilia_Sergeevich [38]3 years ago
8 0
70% of 40 is 28 for summer, 10% of 40 is 4 for winter, 5% of 40 for fall is 2 and the rest, being 15% is 5 people who voted spring. From smallest to largest, it is fall, winter, spring and summer.
kiruha [24]3 years ago
4 0

Answer:

D) the last picture is correct

Explamation example

The pic that has fall that can't fit in the box is the correct one and the almost the whole circle is covered in blue is the correct one

You might be interested in
Twenty students from Sherman High School were accepted at Wallaby University. Of
nydimaria [60]

Answer:

Data provide convincing evidence of a difference in SAT scores  between students with and without a military scholarship is explained below in details.

Step-by-step explanation:

This is a quiz of 2 autonomous groups. The population model differences are not understood. it is a two-tailed examination. Let w be the index for scores of students with army research and o be the index for scores of students without army research.

Therefore, the population means would be μw and μo.

The irregular variable is x w - xo = variation in the sample mean records of students with military accomplishments and students without.

For students with military accomplishments,

n = 8

Mean = (850 + 925 + 980 + 1080 + 1200 + 1220 + 1240 + 1300)/8

Mean = 1099.375

Standard deviation = √(summation(x - mean)/n

Summation(x - mean) = (850 - 1099.375)^2 + (925 - 1099.375)^2 + (980 - 1099.375)^2 + (1080 - 1099.375)^2 + (1200 - 1099.375)^2 + (1220 - 1099.375)^2 + (1240 - 1099.375)^2 + (1300 -1099.375)^2 = 191921.875

Standard deviation = √(191921.875/8 = 154.89

For students without military scholarship,

n = 12

Mean = (820 + 850 + 980 + 1010 + 1020 + 1080 + 1100 + 1120 + 1120 + 1200 + 1220 + 1330)/12

Mean = 1073.83

Summation(x - mean) = (820 - 1073.83)^2 + (850 - 1073.83)^2 + (980 - 1073.83)^2 + (1010 - 1073.83)^2 + (1020 - 1073.83)^2 + (1080 - 1073.83)^2 + (1100 - 1073.83)^2 + (1120 - 1073.83)^2 + (1120 - 1073.83)^2 + (1200 - 1073.83)^2 + (1220 - 1073.83)^2 + (1330 - 1073.83)^2 = 238199.4268

Standard deviation = √(238199.4268/12 = 140.89

We would set up the hypothesis.

The null hypothesis is

H0 : μw = μo H0 : μw - μo = 0

The alternative hypothesis is

Ha : μw ≠ μo Ha : μw - μo ≠ 0

Since sample standard deviation is recognized, we would analyis the examination statistic by using the t examination. The formula is

(xw - xo)/√(sw²/nw + so²/no)

From the information given,

xw = 1099.375

xo = 1073.83

sw = 154.89

so = 140.89

nw = 8

no = 12

t = (1099.375 - 1073.83)/√(154.89²/8 + 140.89²/12)

t = 0.37

The formula for determining the degree of freedom is

df = [sw²/nw + so²/no]²/(1/nw - 1)(sw²/nw)² + (1/no - 1)(so²/no)²

df = [154.89²/8 + 140.89²/12]²/(1/8 - 1)(154.89²/8)² + (1/12 - 1)(140.89²/12)² = 21650688.37/1533492.15

df = 14

We would get the probability count from the t test calculator. It becomes

p value = 0.72

Since the level of importance of 0.05 < the p value of 0.72, we would not neglect the null hypothesis.

Therefore, these data do not present an acceptable indication of a difference in SAT scores between students with and without a military scholarship.

Part B

The formula for getting the confidence interval for the difference of two population means is expressed as

z = (xw - xo) ± z ×√(sw²/nw + so²/no)

For a 95% confidence interval, the z score is 1.96

xw - xo = 1099.375 - 1073.83 = 25.55

z√(sw²/nw + so²/no) = 1.96 × √(154.89²/8 + 140.89²/12) = 1.96 × √2998.86 + 1654.17)

= 133.7

The confidence interval is

25.55 ± 133.7

6 0
3 years ago
If v = 6i + 3j, what is ||-10v||
tia_tia [17]

The values of ||-10v|| is 51.96 units

  • Complex numbers are square roots of negative numbers. They are expressions that consist of both the real and imaginary axis.

  • The general form of a complex number is expressed as z = x + iy

Given the complex number v = 6i + 3j,

10v is expressed as 10(6i + 3j)

10(6i + 3j) = 60i + 30j

Take the modulus of the complex number:

|10v|=\sqrt{60^2+30^2}\\|10v|= \sqrt{1800+900}\\|10v|= \sqrt{2700} \\|10v|=51.96units

Hence the values of ||-10v|| is 51.96 units

Learn more on the complex numbers here: brainly.com/question/10662770

6 0
2 years ago
A cube has side length a. The side lengths are decreased to 40% of their original size. Write an expression in simplest form for
o-na [289]
V=a ^{3} originally. Then you reduces the side lengths a so it will beV=( \frac{2}{5} a)^{3} = \frac{8}{125}a^{3}
Just note that 40% is the same as 2/5.<span />
6 0
2 years ago
The packaging lists a model airplane’s length as 10.5 in. It also gives the scale as 1:83. What is the length of the actual airp
Lana71 [14]
\bf \cfrac{\stackrel{model}{length}}{\stackrel{actual}{length}}\qquad 1:83\qquad \cfrac{1}{83}\implies \cfrac{1}{83}=\cfrac{10.5}{x}\implies x=\cfrac{83\cdot 10.5}{1}&#10;\\\\\\&#10;x=871.5~inches&#10;\\\\\\&#10;\textit{there are 12 inches in 1 foot, thus }&#10;\\\\\\&#10;871.5~\underline{in}\cdot \cfrac{ft}{12~\underline{in}}\implies 72.625~ft &#10;\qquad \approx 73~ft
6 0
3 years ago
Please help me out!!<br><br> 24n = 6 <br> n = ?
Travka [436]
Divide 24 from both sides
5 0
2 years ago
Read 2 more answers
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