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ella [17]
3 years ago
6

4/15:8 3/7:7/10 3.3/5:4.1/2

Mathematics
1 answer:
posledela3 years ago
4 0
I don't understand what you are trying to ask if you post this in question form or add a question I can probably help you other than that I don't think anyone knows what you need help with, I'm sorry sweety
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37.5% 1/3 25% and 3/10 least to greatest
barxatty [35]
25% 3/10 1/3 and 37.5%

.25,.30,.33,.375
7 0
3 years ago
"I'm thinking of a fraction that is equivalent to 3/9
vlabodo [156]

Answer:

1/3

Step-by-step explanation:

6 0
3 years ago
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Please help! files attached.
kotykmax [81]
The first question would be x + (x + 4). This is because Max has $x and Keisha has (x + 4) because she has four MORE THAN Max. I am pretty sure that the second one is A, but I am not positive. The first one is right though. I hope this helps!!!
5 0
3 years ago
Which of the following graphs of exponential functions corresponds to a geometric sequence with a first term of 4 and a ratio of
ser-zykov [4K]

Answer: graph E.


A geometric sequence can be written as:

a_{n} = a_{1} \cdot r^{(n - 1)}

where:

a₁ = first term = 4

r = ratio = 0.5


Substituting the numbers, we have:

a_{n} = 4 \cdot (\frac{1}{2})^{n-1}

or else

f(x) = 4 \cdot (\frac{1}{2})^{x - 1}


This is an exponential function with base less than 1. Therefore, we can exclude graph C (which depicts a linear function), and graphs A and D (which depict an exponential function with base greater than 1).


In order to choose between graph B and E, let's evaluate the function in two different points:

f(1) = 4 \cdot (\frac{1}{2})^{1 - 1} = 4

f(2) = 4 \cdot (\frac{1}{2})^{2 - 1} = 4 \cdot \frac{1}{2} = 2


Therefore, we need to look for the graph passing through the points (1, 4) and (2, 2). That is graph E.




3 0
3 years ago
Read 2 more answers
An accelerated life test on a large number of type-D alkaline batteries revealed that the mean life for a particular use before
zheka24 [161]

Answer:

68.2% of the batteries failed between 17.8 and 20.2 hours.

95.44% of the batteries failed between 16.6 and 21.4 hours.

99.97% of the batteries failed between 15.4 and 22.6 hours.

Step-by-step explanation:

The 68-95-99.7 states that, for a normally distributed sample:

68.26% of the measures are within 1 standard deviation of the sample.

95.44% of the measures are within 2 standard deviations of the sample.

99.97% of the measures are within 3 standard deviations of the sample.

In this problem, we have that:

Mean of 19 hours, standard deviation of 1.2 hours.

About 68.26% of the batteries failed between what two values?

This is within 1 standard deviation of the mean. So 68.2% of the batteries failed between 17.8 and 20.2 hours.

About 95.44% of the batteries failed between what two values?

This is within 2 standard deviations of the mean. So 95.44% of the batteries failed between 16.6 and 21.4 hours.

About 99.97% of the batteries failed between what two values?

This is within 3 standard deviations of the mean. So 99.97% of the batteries failed between 15.4 and 22.6 hours.

5 0
3 years ago
Read 2 more answers
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