4/15:8 3/7:7/10 3.3/5:4.1/2
1 answer:
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Solution:
Data represented as number of hours spent in studying by Group A Students:
1,2,1,1,3,3,2,2,3
Arranging it in ascending order: 1,1,1 ,2, 2, 2, 3, 3, 3,
As number of terms is odd, The median will be middle value of observation.Which is 2.
The Data arranged in ascending order are , (1,1,1,2),2(2,3,3,3).
Median of (1,1,1,2) = =1
Median of (2,3,3,3)==3
=Interquartile Range =
=3-1=2
For Data Set 2,
The Data for group B students are: 3 2 3 2 2 2 1 1 2
Arranging in ascending order: 1,1,2,2,2,2,2,3,3
total number of observation = 9
Median = 2
Arranging the data as : (1,1,2,2) 2,(2,2,3,3)
Median of (1,1,2,2)= Number of observation is 4 which is even , so Median= =
Median of (2,2,3,3)==
S=Interquartile Range = =
Interquartile range for Group A Students =Interquartile range for Group B students + 1
Option (D) The interquartile range for Group A employees is 1 more than the interquartile range for Group B students is true.