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valentinak56 [21]
3 years ago
10

Before sending track and field athletes to the Olympics, the U.S. holds a qualifying meet. The lower dot plot shows the times (i

n seconds) of the 888 sprinters who competed in the final of the women's 100100100-meter dash at the 201220122012 Olympic games. The upper dot plot shows the times (in seconds) of the top 888 sprinters at the U.S. qualifying meet for that event. Which pieces of information can be gathered from these dot plots? (Remember that lower sprint times are faster.) Choose all answers that apply: Choose all answers that apply: (Choice A) A The times in the Olympic final were faster on average than the top 888 U.S. qualifier times. (Choice B) B All of the times in the Olympic final were faster than all of the top 888 U.S. qualifier times. (Choice C) C The Olympic final times varied noticeably more than the times of the top 888 U.S. qualifiers. (Choice D) D None of the above

Mathematics
2 answers:
vladimir2022 [97]3 years ago
6 0

Answer:

A and c

Step-by-step explanation:

Khan

kirill115 [55]3 years ago
4 0

Answer:

A and C

Step-by-step explanation:

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total number of boys and girls in a class is 42. if the number of girls is 10 more than the boys find the number of boys?? answe
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Answer:

\boxed{\sf Total \ number \ of \ boys = 16}

Given:

Total number of boys and girls in class = 42

Total number of girls = 10 more than the boys

To Find:

Total number of boys

Step-by-step explanation:

Let total number of boys be 'x'

\sf So, \\ \sf Total \: number \ of \ girls = x + 10 \\  \\  \therefore \\  \sf \implies    Total \: number \: of \: boys \: and \: girls  \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = Total \: number \: of \: boys + Total \\  \sf \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  number \: of \: girls \\  \\  \sf \implies 42 = x + (x + 10) \\  \\  \sf 42 = x + (x + 10) \: is \: equivalent \: to \: x + (x + 10)  = 42 : \\  \sf \implies x + (x + 10 )= 42 \\  \sf \implies x + x + 10 = 42 \\  \\  \sf x + x = 2x :  \\  \sf  \implies \boxed{ \sf 2x} + 10 = 42

\sf Substrate \: 10 \: from \: both \: sides :   \\  \sf \implies 2x + (10 -  \boxed{ \sf 10}) = 42 -  \boxed{ \sf 10} \\  \\  \sf 10 - 10 = 0 :  \\  \sf \implies 2x = 42 - 10 \\  \\  \sf 42 - 10 = 32 :  \\  \sf \implies 2x =  \boxed{ \sf 32} \\  \\  \sf Divide \: both \ sides \: by \: 2 :  \\  \sf \implies \frac{2x}{ \boxed{ \sf 2}}  =  \frac{32}{ \boxed{ \sf 2}}  \\  \\  \sf \frac{2x}{2}  =  \frac{ \cancel{2}}{ \cancel{2}}  \times (x) = x :  \\  \sf \implies x =  \frac{32}{2}  \\  \\  \sf  \frac{32}{2}  =  \frac{16 \times  \cancel{2}}{ \cancel{2}}  = 16 :  \\  \sf \implies x = 16

So,

Total number of boys = x = 16

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When writing 3.7272727272... as a ratio of integers, what is the common ratio?
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Explanation:
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72/99 = (72÷9) / (99÷9) = 8/ 11 . 

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  "41 / 11" cannot be simplified any further; so the answer is:
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  "41 / 11 " ;  or, write as:  " 41 : 11 " .
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