Help me with this question please

A store pays $423 for a crystal vase and marks the price up by 46%. What is the amount of the mark-up?

jek_recluse [69]

Answer:

194.58$

Step-by-step explanation:

Have a great day! :)

6 0

3 years ago

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An outlier always affects the mean. True False

Ipatiy [6.2K]

Yes. If you have very high or very low outliers in your data set, it is generally preferred to use the median - the mid-point when all data points are arranged from least to greatest.

A good example for when to avoid the mean and prefer the median is salary. The mean is less good here as there are a few very high salaries which skew the distribution to the right. This drags the mean higher to the point where it is disproportionately affected by the few higher salaries. In this case, the median would only be slightly affected by the few high salaries and is a better representation of the whole of the data. 

In general, if the distribution is not normal, the mean is less appropriate than the median.

3 0

4 years ago

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Una bolsa de 18 libras de comida para perros cuesta $27. ¿Cuál es la constante de proporcionalidad que relaciona el costo en dól

castortr0y [4]

Answer:

$k=\frac{y}{x}= \frac{27}{18} = \frac{3}{2}$ = 1 $\frac{1}{2}$

Step-by-step explanation:

5 0

3 years ago

Find the point on the hyperbola xy= 8 that is closet to the point (3,0)

son4ous [18]

The distance $l$ between $(x, y)$ and $(3, 0)$ is:
$l=\sqrt{(0-y)^{2}+(3-x)^{2}}=\sqrt{y^{2}+(3-x)^{2}}$

Since the equation of the hyperbola is $xy=8$ , we can get $y$ by itself and end up with
$y=\frac{8}{x}$

which we can plug into our distance formula:
$l=\sqrt{(\frac{8}{x})^{2}+(3-x)^{2}}$

To make calculation easier, we'll square both sides:
$l^{2}=(\frac{8}{x})^2+(3-x)^{2}$
and create a new variable $m=l^{2}$ :
$m=(\frac{8}{x})^2+(3-x)^{2}$
$\rightarrow m=\frac{64}{x^{2}}+9-6x+x^{2}$

Differentiate both sides:
$\frac{dm}{dx}=-\frac{128}{x^{3}}-6+2x$
Minimum distance is achieved when $\frac{dm}{dx}=0$ :
$-\frac{128}{x^{3}}-6+2x=0$
$\rightarrow -128-6x^{3}+2x^{4}=0$
$\rightarrow 2(x^{4}-3x^{3}-64)=0$
$\rightarrow x^{4}-3x^{3}-64=0$

To find a value of $x$ , you can use methods like synthetic division and get the answer $x=4$

Plug into $xy=8$ :
$4y=8$
$\rightarrow y=2$

So the closest point on the hyperbola to $(3, 0)$ is $(4, 2)$

7 0

3 years ago

Does 5, 5, 10 a right triangl

nydimaria [60]

Answer:

yes it does

Step-by-step explanation:

please mark brainiest.

5 0

3 years ago

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