2x + 3y = -6 (Subtract 2x from both sides)
3y = -2x - 6 (Divide both sides by 3 to isolate x) which will give you y = -2/3x - 2 and this graphed would cross the x-axis at (-3,0) and the y-axis at (0, -2). So a + b = -5
We know that the law of sines states that:

For simplicity, let:

In triangle A1BC this leads to:

Therefore:

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have:
Area formula of a parallelogram is
A = base x height
Given are the
Area = 60 m² and base = 10 m
Substitute the given:
60 = 10h (divide by 10 to find value of h)

(10 and 10 cancels out)
h = 6The
height of a parallelogram with a base of 10m and an area of 60m² is
6m
Turn f(x) into y so the equation is y=x+2. Now switch their places so it is x=y+2. Now solve for y. The answer is y=x-2.