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Bas_tet [7]
3 years ago
12

Write the equation of a line perpendicular to x=6 passing through (3,5)

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
4 0
Line x=6 is vertical, so line which perpendicular to this line is horizontal
so y=a
 line pass throuht point (3;5)
so it is line y=5
Answer: y=5


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sergejj [24]

Answer:

vertically Angle is correct answer

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What is 22 % of 500?
zloy xaker [14]
Its 110 hope dis helps 
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Is 1/9+1/8 closer to 0.5 or 1/2? explain.
xenn [34]

Answer:

Well 0.5 is the same as 1/2 but I'll try to help.

Step-by-step explanation:

1/9+1/8 is 0.2361. That would honestly be closer to zero but the way that it is worded, it is closer to 1/2 because you are using fractions in the problem. If you were using decimals, I would use 0.5

5 0
3 years ago
g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh
Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=10$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

7 0
4 years ago
Use segment addition postulate<br> If k is the midpoint of JL, JK=8x+11 and KL = 14x-1, find JL
labwork [276]
8x+11 =14x-1
x=2
plug 2 into the equations to find the lengths then add them
16+11=27=JK
28-1=27=KL
27+27=54
54=JL
6 0
3 years ago
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