Graph 2: Please help me sketch this graph.
1 answer:
Answer: see answers below
<u>Step-by-step explanation:</u>
y = A cos (Bx - C) + D
- A is the amplitude
- Period = 2π/B → B = 2π/Period
- Phase shift = C/B
- D is the vertical shift (aka midline)
Given: A = 5/2, B = π/6, C = 0, D = 13/2
1) midline (D) ± amplitude (A) = Max & Min
Max: 13/2 + 5/2 = 18/2 = 9
Min: 13/2 - 5/2 = 8/2 = 4
2) Midline (D) is given as 13/2 = 6.5
3) Period = 2π/B = 2π/(π/6) = 12
4) Formula is given as: y = 5/2 cos (π/6)x + 13/2
5) change the coordinates of y = cos (x) and as follows:
- x-value: add C then divide by B
- y-value: multiply by A then add D
Note that A = 5/2, B = π/6, C = 0, D = 13/2
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Answer:
f(x) = 3 + 2
Step-by-step explanation:
Given G(x) =
As we can see, the graph of f(x) is 2 units above the graphof g(x) in vertical (vertical shift)
=> f(x) = a + 2
As you can see, the graph of f(x) is stretched vertically by a dilation factor of 3
and there is no reflection, so a= 3
=> the equation of f(x) is: f(x) = 3 + 2