Q = recessive allele frequency = 0.3, and thus in H-W equilibrium there are ONLY two alleles, q (recessive) and
p (dominant). Therefore all of the p and q present for this gene in a population must account for 100% of this gene's alleles. And 100% = 1.00.
So p, the dominant allele frequency, must be equal to 1 - q --> p = 1 - q
p = 1 - 0.3 = 0.7.
Since heterozygotes are a combination of the p and q, we must again look at the frequencies of each genotype: p + q = 1, then (p+q)^2 = 1^2
So multiplying out (p+q)(p+q) = 1, we get: p^2+2pq+q^2 = 1 (all genotypes), where p^2 = frequency of homozygous dominant individuals, 2pq = frequency of heterozygous individuals, and q^2 = frequency of homozygous recessive individuals.
Therefore if the population is in H-W equilibrium, then the expected frequency of heterozygous individuals = 2pq = 2(0.7)(0.3)
2pq = 2(0.21) = 0.42, or 42% of the population.
Hope that helps you to understand how to solve population genetics problems!
The brain loses 5-10 percent of its weight between the ages 20 & 90.
Answer:
i hope it help
Explanation:
A person's genotype is not determined by their phenotype. The genotype is the genetic makeup of an individual and is the basic instructions for how the cell should make proteins that make up our traits. The phenotype is the physical appearance or characteristics of the person.
Plants store starch which is a complex carbohydrate. This can be broken down into a simple one known as glucose. They then use glucose for energy.
Answer:
did you delete it or no? because that might've happened
Explanation:
it happened to me once
