1. (10 pts.) Suppose you have a language with only 3 letters: A, B, and C, which occur with frequencies 0.7, 0.2, and 0.1, respe
ctively. The following ciphertext was encrypted by the Vigen`ere method: BABABCBCAC. Assume that the key length is either 1, 2, or 3. Find the most likely key length and determine the most likely key using the method from class. Solution: We compare BABABCBCAC with its shifts by 1, 2, and 3, looking for overlaps. There are no overlaps for a shift of 1 or 3, but there are 6 overlaps for a shift of 2. Thus we expect the key length to be 2. Looking at every other letter, we see BBBBA and AACCC for the letters in even and odd positions, respectively. Due to the overwhelming frequency of the letter A in the language, we can reasonably assume that B decrypts to to A in the first sequence and C decrypts to A in the second. This gives us the key BC.
1 answer:
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Line 1--------- >(0,2) (1,-1)
y=mx+b m=(-1-2)/(1-0)=-3
2=(-3)*(0)+b----- > b=2
y1=-3x+2
Line 2--------- >(0,-1) (2,2)
y=mx+b m=(2+1)/(2-0)=3/2
-1=(3/2)*(0)+b----- > b=-1
y2=(3/2)x-1
<span>using a graphic tool
see attached figure</span>
the best estimate solution for the system is <span>(1, 1)
because </span>is the only one within the range of the x axis (-5,5) and the y axis (-5,5)
y=mx+b m=(-1-2)/(1-0)=-3
2=(-3)*(0)+b----- > b=2
y1=-3x+2
Line 2--------- >(0,-1) (2,2)
y=mx+b m=(2+1)/(2-0)=3/2
-1=(3/2)*(0)+b----- > b=-1
y2=(3/2)x-1
<span>using a graphic tool
see attached figure</span>
the best estimate solution for the system is <span>(1, 1)
because </span>is the only one within the range of the x axis (-5,5) and the y axis (-5,5)