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Digiron [165]
3 years ago
6

1. (10 pts.) Suppose you have a language with only 3 letters: A, B, and C, which occur with frequencies 0.7, 0.2, and 0.1, respe

ctively. The following ciphertext was encrypted by the Vigen`ere method: BABABCBCAC. Assume that the key length is either 1, 2, or 3. Find the most likely key length and determine the most likely key using the method from class. Solution: We compare BABABCBCAC with its shifts by 1, 2, and 3, looking for overlaps. There are no overlaps for a shift of 1 or 3, but there are 6 overlaps for a shift of 2. Thus we expect the key length to be 2. Looking at every other letter, we see BBBBA and AACCC for the letters in even and odd positions, respectively. Due to the overwhelming frequency of the letter A in the language, we can reasonably assume that B decrypts to to A in the first sequence and C decrypts to A in the second. This gives us the key BC.

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Answer:

The solution to this question is attached below:

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6k ÷ 7 = -3<br> Solve for k
fomenos

Answer:

k = -3.5

Step-by-step explanation:

6k ÷ 7 = -3

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Divide both sides by 6

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To check if the answer is correct or not, you can always plug in -3.5 for k in the equation.

6(-3.5) ÷ 7 = -3

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2

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