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Evgesh-ka [11]
2 years ago
6

How do you convert minutes to seconds

Mathematics
2 answers:
alex41 [277]2 years ago
5 0
Multiply the amount of minutes by 60 to find seconds, M * 60 = S
Musya8 [376]2 years ago
5 0
Multiply 60 by the number of mins to get the number of seconds
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The slope of the line that passes through the points (-10,y) and (5, 2) is 2/5. What is the value of y?
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Answer:

C, -4

Step-by-step explanation:

slope=change in y/change in x

\frac{2 - y}{5 - ( - 10)}  =  \frac{2}{5}

\frac{2 - y}{5  + 10}  =  \frac{2}{5}

multiply both sides by 2/5

2 - y =  \frac{2}{5} (5 + 10)

simplify the right side. 2/5 × 5 = 2 and 2/5 × 10 = 4

2 - y = 2 + 4

2 - y = 6

bring y to the other side by adding y on both sides

2 = 6 + y

subtract 6 on both sides

2 - 6 = y

so y is -4

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Melanie is making a piece of jewelry that is in the shape of a right triangle. The two shorter sides of the piece of jewelry are
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Using Pythagoras’ theorem a2 + b2 = c2 you can find out the third (longest) side. (6x6) + (8x8) = 100 (the square root of 100 is 10) so ur final sum is 6+8+10 = 24 mm
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3 years ago
A pyramid-shaped vat has square cross-section and stands on its tip. The dimensions at the top are 2 m × 2 m, and the depth is 5
Strike441 [17]

Answer:

the water level increases at a rate of 1.718 m/min when the depth is 4 m

Step-by-step explanation:

the volume of the pyramid is

V = (1/3)(height)(area of base) = 1/3 H*L²

For the diagonal in the pyramid

tg Ф = Side Length/ Height = L / H = x / h

where h= depth of water , x= side of the corresponding cross section

therefore x= L *h/H

the volume of the water is

v= 1/3 h*x² = 1/3 (L/H)² h³

in terms of time

v = Q*t

then

Q*t = 1/3 (L/H)² h³

h³ = 3*(H/L)² *Q *t

h = ∛(3*(H/L)² *Q *t) = ∛(3*(H/L)² *Q) *∛t = k* ∛t , where k=∛(3*(H/L)² *Q)

h = k* ∛t

then the rate of increase in depth is dh/dt

dh/dt = 1/3*k* t^(-2/3)

since

t = (h/k)³

dh/dt = 1/3*k* t^(-2/3) = 1/3*k* (h/k)³ ^(-2/3)  = 1/3*k* (h/k)^(-2) = 1/3 k³ / h²

=  1/3 (3*(H/L)²*Q) / h²  = (H/L)²*Q /h²

dh/dt= [H/(h*L)]²*Q

replacing values, when h=4m

dh/dt= [H/(h*L)]²*Q  = [5m/(4m*2m)]² * (3m³/min)= 1.718 m/min

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3 years ago
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