Question

E^(2x) — 3e^x + 2 = 0 Solve for x

Answer 1

You can essentially treat this equation as a factorable quadratic, with the variable being $e^x$:

$e^{2x} - 3e^x + 2 = 0$
$(e^x - 2)(e^x - 1) = 0$
$e^x = 1, 2$
$x = \ln 1, \ln 2 = 0, \ln 2$