We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.
You can a linear equation when the line go between the margin and when it have a straight line
Answer: i believe the answer is 10
Step-by-step explanation:
Answer:
<h2>B.
5027 in²</h2><h2>
</h2>
Step-by-step explanation:
Area of a circle = π r²
where r = 80/2 = 40 in
<u>plugin value of r=40in into the formula:</u>
Area of a circle = π r²
= π (40)²
= 5027 in²
Supposing 2x-7 were a factor, then 7/2 would be a root. Use synth. div. to determine whether 7/2 actually is a root:
__________________________
7/2 / 6 -21 -4 24 -35
21 0 -14 35
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6 0 -4 10 0
Since the remainder is zero, 7/2 is a root and 2x - 7 is a factor.
You could check out the other possible factors in the same manner.