All categories

3 years ago

Which representation of a transformation on a coordinate grid preserves congruence?

Mathematics

1 answer:

Zepler [3.9K]3 years ago

3 0

Answer:

Rotations, reflections and translations.

Step-by-step explanation:

Rotations, reflections and translations are transformations that preserve the both the angle measurements and the lengths of the sides, so congruence is preserved.

Dilations are transformations that keep the angle measurements, but the side lengths change, so the transformation is similar, not congruent.

You might be interested in

What are all the composite numbers from 1 to 100

Anastaziya [24]

Answer:

4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20, 21, 22, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 36, 38, 39, 40, 42, 44, 45, 46, 48, 49, 50, 51, 52, 54, 55, 56, 57, 58, 60, 62, 63, 64, 65, 66, 68, 69, 70, 72, 74, 75, 76, 77, 78, 80, 81,82, 84, 85, 86, 87, 88, 90, 91, 92, 93, 94, 95, 96, 98, 99, 100.

Step-by-step explanation:

its pretty simple...

6 0

2 years ago

PLSSSS HELPPP<br><br> 4 ¼ divided by 2 ½

notsponge [240]

Answer:

1.7 or 1 7/10

Step-by-step explanation:

5 0

2 years ago

Add −2/3+2 3/8 . Write your answer as a mixed number in simplest form.

d1i1m1o1n [39]

Answer:

41/24 or 1 17/24

Step-by-step explanation:

2 3/8=19/8

-2/3+19/8

-16/24+57/24

41/24

5 0

2 years ago

Read 2 more answers

2865 students participated in a competitive exam. There were 60 rooms in the

sladkih [1.3K]

47 students per room, 45 weren’t in a room

5 0

2 years ago

Help!! Find missing value for each quadratic function

Svetllana [295]

I'll do the first one to get you started. The answer is -3

=================================================

Explanation:

When x = -1, y = 0 as shown in the first column. The second column says that (x,y) = (0,1) and the third column says (x,y) = (1,0)

We'll use these three points to determine the quadratic function that goes through them all.

The general template we'll use is y = ax^2 + bx + c

------------

Plug in (x,y) = (0,1). Simplify

y = ax^2 + bx + c

1 = a*0^2 + b*0 + c

1 = 0a + 0b + c

1 = c

c = 1

------------

Plug in (x,y) = (-1,0) and c = 1

y = ax^2 + bx + c

0 = a*(-1)^2 + b(-1) + 1

0 = 1a - 1b + 1

a-b+1 = 0

a-b = -1

a = b-1

------------

Plug in (x,y) = (1,0), c = 1, and a = b-1

y = ax^2 + bx + c

0 = a(1)^2 + b(1) + 1 ... replace x with 1, y with 0, c with 1

0 = a + b + 1

0 = b-1 + b + 1 ... replace 'a' with b-1

0 = 2b

2b = 0

b = 0/2

b = 0

------------

If b = 0, then 'a' is...

a = b-1

a = 0-1

a = -1

------------

In summary so far, we found: a = -1, b = 0, c = 1

Therefore, y = ax^2 + bx + c turns into y = -1x^2 + 0x + 1 which simplifies to y = -x^2 + 1

------------

The last thing to do is plug x = 2 into this equation and simplify

y = -x^2 + 1

y = -2^2 + 1

y = -4 + 1

y = -3

3 0

3 years ago