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Sliva [168]
4 years ago
14

What is a typical relationship between time and interest rate

Business
2 answers:
Misha Larkins [42]4 years ago
7 0
Typically there is a correlation as time passes, interest rates go up. That is great for investments but not so good for debt.
slava [35]4 years ago
6 0

Answer:  interest rate

Explanation:  Longer time period usually equals higher interest rates.  

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The Tax Equity and Fiscal Responsibility Act of 1982 (TEFRA) resulted in implementation of risk contracts, which are arrangement
Sever21 [200]

Answer:

Capitated

Explanation:

Based on the information given the implementation of the risk contracts by TEFRA is to ensure that are medical arrangements are made among providers in order to provide CAPITATED health care services to Medicare beneficiaries.

CAPITATED health care services can be seen as the way in which medical treatment payment are made to the providers of health care service in advance for the sole aim of providing medical services or treatment to patient which are the Medicare beneficiary that have registered and assigned to them for a specific period of time.

6 0
3 years ago
Hair World Inc. is a wholesaler of hair supplies. Hair World uses a perpetual inventory system. The following transactions (summ
marin [14]

Answer:

Net Sales

Gross Revenue                                           $‭101,200

Less:

Sales Discount                         $288

Sales Returns                          <u> $1,000 </u>      <u>  $1,288</u>

Net Sales                                                      $‭99,912‬‬

Gross revenue  = 83,200 + 18,000 = $‭101,200‬

Gross Profit

Net Sales                                                      $‭99,912‬

Less: Cost of Goods sold                           <u> ($‭52,747‬)</u>

Gross Profit                                                  $‭‭47,165‬

Cost of goods sold

= 44,797 - 600 + 8,550

= $‭52,747‬

7 0
4 years ago
A pharmacy company wants to add flu shots to its list of services. It releases a code for free shots online using____ . It creat
Gnom [1K]
1 is social meadia 2 is advertising and 3 is publicity
5 0
3 years ago
Read 2 more answers
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
4 years ago
2. Sally Medavoy will invest $8,000 a year for 3 years in a fund that will earn 10% annual interest. If the first payment into t
ipn [44]

Answer: $10,746

Explanation:

Using Compound interest formula

A= p(1+r/n) *nt

A= final amount =?

P= initial principal =$8, 000

r = interest rate = 0.1

n= nob of times interest applied(3)

t=nob of times period elapsed (3)

A = 8,000 (1+0.1/3) *9

A = 8000 (3+0.1/3) *9

A= 8000 (3.1/3) *9

A = 8000 (1.0333) *9

A = 8000 × 1.34327

A= $10,746

5 0
3 years ago
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