Answer:
yes (i think im not for sure)
Step-by-step explanation:
Answer:
A. {x,y}={-2,-3}
// Solve equation [2] for the variable x
[2] x = 2y + 4
// Plug this in for variable x in equation [1]
[1] (2y+4) - y = 1
[1] y = -3
// Solve equation [1] for the variable y
[1] y = - 3
// By now we know this much :
x = 2y+4
y = -3
// Use the y value to solve for x
x = 2(-3)+4 = -2
B. [1] 3x=3y-6
[2] y=x+2
Equations Simplified or Rearranged :
[1] 3x - 3y = -6
[2] -x + y = 2
Solve by Substitution :
// Solve equation [2] for the variable y
[2] y = x + 2
// Plug this in for variable y in equation [1]
[1] 3x - 3•(x +2) = -6
[1] 0 = 0 => Infinitely many solutions
C.Step by Step Solution
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System of Linear Equations entered :
[1] 4x - y = 2
[2] 8x - 2y = 4
Solve by Substitution :
// Solve equation [1] for the variable y
[1] y = 4x - 2
// Plug this in for variable y in equation [2]
[2] 8x - 2•(4x-2) = 4
[2] 0 = 0 => Infinitely many solutions
6x^2 +30x - 36
6( x^2 +5x -6)
6(x^2 -x+6x-6)
6[ x(x-1) 6(x-1)]
(x-1) (x+6)
Devon read 65 pages in total. Hope this helps!