Show how to make a ten to solve 3

One number is 4 more than another, and their sum is 60. What is the smaller number? If x = the larger number and y = the smaller

erik [133]

Answer:

a. $x+y=60$ and $-x+y=4$

Step-by-step explanation:

Let x be the larger number and y be the smaller number.

We have been given that one number is 4 more than another. We can represent this information in an equation as:

$y=x+4...(1)$

We can manipulate this equation as:

$y-x=x-x+4$

$-x+y=4$

We are also told that the sum of both numbers is 60. We can represent this information in an equation as:

$x+y=60...(2)$

Upon looking at our given choices, we can see that option 'a' is the correct choice.

8 0

3 years ago

Read 2 more answers

You deposit $500 in a savings account that earns 9% annual interest compounded monthly. Write a function that represents the bal

faltersainse [42]

The function would be : y=(500)(9t)

7 0

3 years ago

Find out the value of X, if√x=9 <br>

weeeeeb [17]

To find this answer, take both sides of the equality and square them:

(√×²)=9²

This gives you:

×=81

5 0

3 years ago

Read 2 more answers

The quadratic model f(x)=-5x^2 +200 represents the approximate height, in meters, of a ball x seconds

katrin [286]

Answer:

x = 5.477 s

Step-by-step explanation:

Your full question can be found in the image below

We can easily solve this question by using a graphing tool or calculator to plot the equation

f(x)=-5x^2 +200

See second attached picture

The ball is 50 meters from the ground when

50 =-5x^2 +200

-150 =-5x^2

x^2 = 30

x = 5.477 s

3 0

4 years ago

A croissant shop has plain croissants, cherry croissants, chocolate croissants, almond croissants, apple croissants, and broccol

slamgirl [31]

Answer:

A. 6 188

B. 749 398

C. 6 188

D. 52 975

E. 20 349

F. 11 316

Explanation:

(a) The shop has 6 types of croissants of which a dozen(12) has to be selected

Therefore n=6, r=12

Repetition of croissants is permitted

And C(n+r-1, r)

C(6+12-1, 12) = C(17, 12) = 17!÷ 12!(17-12)! = 17!÷12! 5! =6 188

(b) The shop has 6 types of croissants of which three dozen(36) has to be selected

Therefore n=6, r=36

Repetition of croissants is permitted

And C(n+r-1, r)

C(6+36-1, 12) = C(41, 36) = 41!÷ 36!(41-36)! = 41!÷36! 5! = 749 398

(c) The shop has 6 types of croissants of which two dozen(24) has to be selected

Let us first select 2 of each kind which 12 croissants in total. Then we still need to select the remaining 12 croissants

Therefore n=6, r=12

Repetition of croissants is permitted

And C(n+r-1, r)

C(6+12-1, 12) = C(17, 12) = 17!÷ 12!(17-12)! = 17!÷12! 5! =6 188

(d) The shop has 5 types of croissants of which two dozen(24) has to be selected

Therefore n=5, r=24

Repetition of croissants is permitted

And C(n+r-1, r)

C(5+24-1, 24) = C(28, 24) = 28!÷ 24!(28-24)! = 28!÷24! 4! = 20 475

5 0

4 years ago

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