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kenny6666 [7]
3 years ago
7

Assume that a program consists of integer and floating-point instructions. 60% of the total execution time is spent on floating

point instructions and the remaining 40% is on integer instructions. How much faster should we run the floating-point instructions to execute entire program 1.25 times faster
Computers and Technology
1 answer:
Ymorist [56]3 years ago
5 0

Answer:

the floating-point instructions  should be run 1.5 times faster in order to execute entire program 1.25 times faster

Explanation:

Given that:

a program consists of integer and floating-point instructions. 60% of the total execution time is spent on floating point instructions and the remaining 40% is on integer instructions.

Let the integer be the total execution time = V

The  floating-point instructions = 60%

The integer instruction = 40%

The time spent on the floating-point instruction = 60/100 × V

= 0.6 V

The time spent on t he integer instruction = 40/100 × V

= 0.4 V

However; How much faster should we run the floating-point instructions to execute entire program 1.25 times faster

If we are to execute the entire program 1,25 times faster;

The new execution time = V/1.25

Assuming the new time spent on floating-point instruction = W

∵

W + 0.4 V = V/1.25

W = V/1.25 - 0.4 V

W = (V - 0.5V)/1.25

W = 0.4V

the new time spent on floating-point instruction = W = 0.4 V

The speed required to make the floating -point instruction to run faster = 0.6V/.4 V

= 1.5

Hence,  the floating-point instructions  should be run 1.5 times faster in order to execute entire program 1.25 times faster

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Write a program that will input the names, ages and weights of three siblings and display the lightest followed by the youngest
jekas [21]

Answer:

Here is the JAVA program:

Sibling.java class:

import java.util.Scanner;  //to accept input from user

public class Sibling {  //class name

//private data members of class

   private String name;  // String type variable to hold the name of sibling

   private int age;  // int type variable to hold the age of sibling

   private int weight;  // int type variable to hold the weight of sibling

   public Sibling() {}     //constructor of class Sibling

   public Sibling (String n, int a, int w)  {  //parameterized constructor

       name = n;  // refers to name field

       age = a;  // refers to age field

       weight = w;    }   // refers to weight field

   public String getName ()    {   //accessor method to get the current name of sibling

       return name;    }   //returns the name field of the sibling

   public int getAge ()    {   //accessor method to get the current age of sibling

       return age;    }   //returns the age field of the sibling

   public int getWeight (){ //accessor method to get the current weight of sibling

    return weight;    } //returns the weight field of the sibling

   public void getInput() {    //to take input name,age and weight from user

 Scanner input = new Scanner(System.in);  //Scanner class object

 System.out.print("Enter the name:  ");  //prompts user to enter the name of sibling

 name = input.nextLine();  //scans and reads the input name from user

 System.out.print("Enter the age:  ");  //prompts user to enter the age of sibling

 age = input.nextInt();   //scans and reads the age from user

 System.out.print("Enter the weight:  ");  //prompts user to enter the weight of sibling

 weight = input.nextInt(); } }   //scans and reads the input weight from user

Explanation:

Here is the TestSibling class that contains main method:

public class TestSibling {   //class name

public static void main (String[] args) {   //main method

String name;  // to hold name of sibling

int age, weight;   // to hold age and weight of sibling

Sibling sib1, sib2, sib3;   // objects of Sibling class

sib1 = new Sibling ();  // creates object of class Sibling for sibling 1 and calls constructor

sib1.getInput();   // calls getInput method using sib1 object to get the name, age and weight of sibling 1

sib2 = new Sibling ();  // creates object of class Sibling for sibling 2 and calls constructor

sib2.getInput();   //calls getInput method using sib2 object to get the name, age and weight of sibling 2

sib3 = new Sibling ();  //creates object of class Sibling for sibling 3 and calls constructor

sib3.getInput();   //calls getInput method using sib3 object to get the name, age and weight of sibling 3

Sibling youngest=null, lightest=null;    //holds the youngest age and lightest weight of siblings

if (sib1.getAge( )<= sib2.getAge( ) && sib1.getAge( ) <= sib3.getAge( ) )   /*if condition checks if age of sibling 1 is less than or equals to that of sibling 2 and sibling 3,  using object of each sibling and getAge method to access age. the logical operator && AND is used so that if condition evaluates to true if sib1 is younger than both sib2 and sib3 */

{ youngest=sib1;}   //if the above condition is true then sets sib1 as youngest

else if (sib2.getAge( ) <= sib1.getAge( ) && sib2.getAge( ) <= sib3.getAge( ) )   // else if condition checks if age of sibling 2 is less than or equals to that of sibling 1 and sibling 3

{youngest=sib2;}   // if above condition is true then sets sib2 as the youngest

else   //if none of the above condition is true then this means that the third has the lowest age

{            youngest=sib3;    }    //sets sib3 as the youngest

if (sib1.getWeight( ) <= sib2.getWeight( ) && sib1.getWeight( ) <= sib3.getWeight( ) )   //if condition checks if weight of sibling 1 is less than or equals to that of sibling 2 and sibling 3,  using object of each sibling and getAge method to access weight of each sibling

          { lightest=sib1; }   //if the above condition is true then sets sib1 as having the lightest weight

else if (sib2.getWeight( ) <= sib1.getWeight( ) && sib2.getWeight( ) <= sib3.getWeight( ) )  // else if condition checks if weight of sibling 2 is less than or equals to that of sibling 1 and sibling 3

{lightest=sib2; }  //if the above condition is true then sets sib2 as the lightest

else  //if none of the above condition is true then this means that the third has the lightest weight

{ lightest=sib3;   }  //sets sib3 as the lightest

System.out.println("The lightest sibling: " + lightest.getName() +" " + lightest.getAge()+" "+ lightest.getWeight());  } } //calls the getName() getAge() and getWeight() method using object lightest to print the lightest of the siblings

System.out.println("The youngest sibling: " + youngest.getName() +" " + youngest.getAge()+" "+ youngest.getWeight());  //calls the getName() getAge() and getWeight() method using object youngest to print the youngest of the siblings

The screenshot of the output is attached.

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Answer:

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Explanation:

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With NAT, businesses can use many internal IP addresses since they are just for internal purposes and will be eventually converted into a single or a few multiple routable IP addresses.

Three types of NAT are possible:

(i) Static NAT : There is a one - to - one mapping between private IP addresses and routable (public) IP addresses. One private IP is mapped to one public IP address.

(ii) Dynamic NAT : There is a many- to - many mapping between private IP addresses and routable (public) IP addresses. Multiple private IPs are mapped to many public IP addresses.

(iii) Port Address Translation (PAT) : Many - to - one relationship between the private IP addresses and public addresses. Many private IP addresses can be mapped or translated into a single public IP address. This type of NAT is also called NAT overload.

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