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I am Lyosha [343]
3 years ago
6

Helpppp with question above pleaseee^^^^

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0
C=2b
d=c+7
b+c=57⇒b+2b=57⇒3b=57⇒ b=19, c=2*19=38, d=38+7=45
thats given

lets find if there is an x such that  d-x=b+x=c⇔ 43-x=19+x=38
43-x=38⇒x=43-38=5
19+x=38⇒x=19
there is no single x (cant be both 5 and 19)
so, i think dan was incorrect.





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PLZ SHOW ALL WORK
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Part I
We have the size of the sheet of cardboard and we'll use the variable "x" to represent the length of the cuts. For any given cut, the available distance is reduced by twice the length of the cut. So we can create the following equations for length, width, and height.
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height: h = x

Part II
v = l * w * h
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v = (216 - 36x - 24x + 4x^2)x
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Part III
The length of the cut has to be greater than 0 and less than half the length of the smallest dimension of the cardboard (after all, there has to be something left over after cutting out the corners). So 0 < x < 6

Let's try to figure out an x that gives a volume of 224 in^3. Since this is high school math, it's unlikely that you've been taught how to handle cubic equations, so let's instead look at integer values of x. If we use a value of 1, we get a volume of:
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Too small, so let's try 2.
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v = 4*2^3 - 60*2^2 + 216*2
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v = 32 - 240 + 432
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And that's the desired volume.
So let's choose a value of x=2.
Reason?
It meets the inequality of 0 < x < 6 and it also gives the desired volume of 224 cubic inches.
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Answer:

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