Alright, so 2x+2=0 (with x being the number) is what I'm getting from this. Subtract 2 from both sides to get 2x=-2, and then divide by 2 to get x=-1
Answer:
see below
Step-by-step explanation:
a. Has a slope of 2 and passes through (10,17)
Using the slope intercept form
y = mx+b where m is the slope and b is the y intercept
y = 2x+b
Substitute the point into the equation
17 = 2(10)+b
17 = 20+b
Subtract 20 from each side
17-20 =b
-3 =b
y = 2x-3
b. passes through (1,-4) and (2,-5)
First find the slope
m= (y2-y1)/(x2-x1)
= (-5- -4)/(2-1)
= (-5+4)/(2-1)
= -1/1
= -1
Using the slope intercept form
y = -x+b
Substitute a point into the equation
-4 = -1(1) +b
-4 = -1+b
Add 1 to each side
-3 = b
y = -x+3
We need the cross product of the two vectors.
a x b
=<2,-2,-3> x <3,2,2>
=
i j k
2 -2 -3
3 2 2
=<-4+6, -(4+9), 4+6>
=<2,-13,10>
The second vector is obtained by reversing the direction, namely <-2,13,-10>
Thus the two vectors are <2,-13,10> and <-2,13,-10>.
