Answer:
9 and 11
Step-by-step explanation:Let the 2 consecutive odd integers be n and n+2.
n(n + 2) = 99
Solve for n.
n2 + 2n - 99 = 0
(n + 11)(n - 9) = 0 ⇒
Two solutions:
n = -11
n + 2 = -9
and
n = 9
n + 2 = 11
Test the answers.
Find the value of -6(-2)^2 - 4^2 - 3(-2x^4).
-6(-2)^2 - 4^2 - 3(-2x^4)
Multiply -6(-2)^2.
12^2 - 4^2 - 3(-2x^4)
Subtract 12^2 and -4^2.
8 - 3(-2x^4)
Distribute -3(-2x^4).
8 + 6x^4
Therefore the value of 6(-2)^2 - 4^2 - 3(-2x^4) is 8 + 6x^4.
Step-by-step explanation:
The system of equations for eq 1 which is 3x + y = 118 represents the Green High School which filled three buses(with a specific number of students identified as x) and a van(with a specific number of students identified as y) with a total of 118 students.
for eq 2; 4x + 2y = 164; represents Belle High School which filled four buses(with a specific number of students identified as x) and two vans(with a specific number of students identified as y) with a total of 164 students.
The solution represents the specific number of students in the buses and vans in eq1 and eq 2 with x being 36 students and y being 10 students.
substituting 36 for x and 10 for y in eq 1;
3(36) + 10 = 108 + 10 = 118 total students for Green High School
substituting 36 for x and 10 for y in eq2;
4(36) + 2(10) = 144 + 20 = 164 total students for Belle High school
