Total = 65
65-23=42
42/3=14
Each necklace = $14
Answer:
rotate it 90 degrees to the right
Step-by-step explanation:
it should line up that way sorry if i'm wrong
Answer:
Generally the barrier width is ![a = 1.9322 *10^{-9} \ m](https://tex.z-dn.net/?f=a%20%3D%201.9322%20%2A10%5E%7B-9%7D%20%5C%20m)
Step-by-step explanation:
From the question we are told that
The tunneling probability required is ![T = 1 * 10^{-5}](https://tex.z-dn.net/?f=T%20%20%3D%201%20%2A%2010%5E%7B-5%7D)
The barrier height is ![V_o = 0.4 eV](https://tex.z-dn.net/?f=V_o%20%20%3D%200.4%20eV)
The electron energy is ![E = 0.08eV](https://tex.z-dn.net/?f=E%20%3D%200.08eV)
Generally the wave number is mathematically represented as
![k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%20m%20%5BV_o%20-%20E%5D%7D%7B%5C%3D%20h%5E2%7D%20%7D)
Here m is the mass of the electron with the value ![m = 9.11 *10^{-31} \ kg](https://tex.z-dn.net/?f=m%20%20%3D%20%209.11%20%2A10%5E%7B-31%7D%20%5C%20%20kg)
h is is know as h-bar and the value is ![\= h = 1.054*10^{-34} \ J \cdot s](https://tex.z-dn.net/?f=%5C%3D%20h%20%3D%201.054%2A10%5E%7B-34%7D%20%5C%20%20J%20%5Ccdot%20s)
So
![k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }](https://tex.z-dn.net/?f=k%20%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%20%2A%209.11%20%2A10%5E%7B-31%20%7D%20%5B0.4%20-%200.04%5D%20%2A%201.6%2A10%5E%7B-19%7D%7D%7B%5B1.054%2A10%5E%7B-34%7D%5E2%5D%7D%20%7D)
=> ![k = 3.073582 *10^{9} \ m^{-1}](https://tex.z-dn.net/?f=k%20%3D%203.073582%20%2A10%5E%7B9%7D%20%20%5C%20m%5E%7B-1%7D)
Generally the tunneling probability is mathematically represented as
![T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}](https://tex.z-dn.net/?f=T%20%20%3D%2016%20%2A%20%5Cfrac%7BE%7D%7BV_o%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7BE%7D%7BV_o%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%20k%20%2A%20a%7D)
So
![1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=1.0%20%2A10%5E%7B-5%7D%20%3D%2016%20%2A%20%5Cfrac%7B0.04%7D%7B0.4%20%7D%20%20%2A%20%5B1%20-%20%5Cfrac%7B0.04%7D%7B0.4%7D%20%5D%20%2A%20e%5E%7B-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> ![6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=6.944%2A10%5E%7B-6%7D%3D%20e%5E%7B-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
Taking natural log of both sides
![ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=ln%5B6.944%2A10%5E%7B-6%7D%5D%20%3D%20-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> ![-11.8776 = -2 * 3.0736 *10^{9} * a}](https://tex.z-dn.net/?f=-11.8776%20%20%3D%20-2%20%2A%203.0736%20%2A10%5E%7B9%7D%20%2A%20a%7D)
=> ![a = 1.9322 *10^{-9} \ m](https://tex.z-dn.net/?f=a%20%3D%201.9322%20%2A10%5E%7B-9%7D%20%5C%20m)
Answer:
Step-by-step explanation:
y=-6x
slope=-6
slope of line ⊥ to given line=1/6
eq. of reqd. line is
y+2=-1/6 (x+1)
6y+12=-(x+1)
or
6y+12=-x-1
6y+x=-1-12
or 6y+x=-13