Answer:
The ball will go to maximum height of 56.25 meters.
Step-by-step explanation:
It is given that, a ball is thrown vertically upward from the ground. Initial velocity of the ball, v = 60 ft/sec
Initial height is 0 as the ball is thrown from ground. The equation of projectile is given by :
h = 0
..............(1)
We need to find the maximum height reached by the ball. For maximum height,
t = 1.875 seconds
Put the values of t in equation (1). So,
h(t) = 56.25 meters
So, the ball will go to maximum height of 56.25 meters. Hence, this is teh required solution.
I can show you on a piece of paper
Hope this helps *smiles*
Answer:
The correct answer would be D) 4.8x + 1.2 = 3.6; x = 0.5 mile
Step-by-step explanation:
This is because laps would be the dependent variable, so we know the number of them (4.8) would be multiplied by the variable (x). We also know that 1.2 is the constant. Now we can solve to make sure this is the right equation.
4.8x + 1.2 = 3.6
4.8x = 2.4
x = 0.5
<span>A. Lines that go up from left to right should have a positive slope.
B. Lines that go down from left to right should have a negative slope.
</span><span>D. The slope of a steep line should be bigger than the slope of a flat line.
E. The slope of a steep line should be smaller than the slope of a flat line.</span>
