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3 years ago

How do I work out this problem?

Mathematics

1 answer:

cluponka [151]3 years ago

4 0

First we need to find ∡PRQ. To do this we can use the fact that the sum of the interior angles of a triangle is 180°:

$180=R+P+Q$
$180=R+40+105$
$180=R+145$
$R=180-145$
$R=35$

Now, we can use the fact that a strait line (like SRQ) is also 180°:
$SRQ=180-R$
$SRQ=180-35$
$SRQ=145$ °

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Find points and graph the following equation. Is this a linear graph? -5x + 6y = 2

anastassius [24]

Answer:

Yes

Step-by-step explanation:

It is a linear graph.

4 0

3 years ago

Hi hope ur having a great day but can u help me. Please. At least do up to number 4 but if u do the rest I will give brain list

lesya692 [45]

Answer:

2. 1400

3.4832

4. 1400

Step-by-step explanation:

8 0

2 years ago

Find a function where f(0)=2 and f(1)=2

xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

$f(x) = 2$ is a valid solution.

Want something more fun? Why not a parabola? $f(x)= ax^2+bx+c$ .

At this point you have three parameters to play with, and from the fact that $f(0)=2$ we can already fix one of them, in particular $c=2$ . At this point I would recommend picking an easy value for one of the two, let's say $a= 1$ (or even $a=-1$ , it will just flip everything upside down) and find out b accordingly: $f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1$

Our function becomes

$f(x) = x^2-x+2$

Notice that it works even by switching sign in the first two terms: $f(x) = -x^2+x+2$

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: $f(x) = A cos (kx)$

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need $A= 2$ , and at that point the first condition is guaranteed; using the second to find k we get $2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi$

$f(x) = 2cos(2\pi x)$

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

$f(x)= 2+sin(2\pi x)$

Sky is the limit.

8 0

3 years ago

Line segments JK and JL in the xy-coordinate plan both have a common endpoint J(-4,11) and midpoints at M1 (2,16) and M2 (-3,5),

OleMash [197]

The first part of the question is not needed
we only need to know M1 and M2
(y2-y1)^2+(x2-x1)^2=(your answer)^2
(5-16)^2+(-3-2)^2=(your answer)^2
(-11)^2+(-5)^2=(your answer)^2
121+25=(your answer)^2
146=(your answer)^2
√146=12.0830459735945721
nearest tenth=12.1

6 0

4 years ago

The Walking Club is one of the after-school activities at Jefferson Middle School.

saveliy_v [14]

You first need to know how much miles it takes on the trail. Then you look 20 x 3 is one hour. And if the 3 group said it takes 2 hours waking for them its like this, the first group takes one hour to go thru the trail, but the second group takes and hour and half the 3 group takes 2 hours.

I wish this helps. :)

4 0

3 years ago