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nikitadnepr [17]
3 years ago
9

In a certain lottery, five different numbers between 1 and 20 inclusive are drawn. To win the lottery, a person must select the

correct 5 numbers in the same order in which they were drawn. What is the probability of winning?
Mathematics
2 answers:
kirill [66]3 years ago
4 0
The probability of winning is 1/20P5 = 1/1,860,480
bulgar [2K]3 years ago
3 0

Answer:

The probability is:

\dfrac{1}{1860480}

Step-by-step explanation:

It is given that:

In a certain lottery, five different numbers between 1 and 20 inclusive are drawn.

Now the number of ways it could be done i.e. number of ways a number can be drawn is:

<em>At the first place we can draw any of the 20 numbers, at the next draw we have 189 choices at the third draw we have 18 choices at fourth we have 17 choices and at the final and last draw we have 16 choices.</em>

Hence the number of ways of drawing=20×19×18×17×16=1860480.

This means the total outcomes=1860480.

Also the number of ways of choosing the number in the same order in which they were drawn=1.

Hence, the probability is:

\dfrac{1}{1860480}

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n200080 [17]

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Step-by-step explanation:

a)  Let's assume that among the four consecutive numbers, the first one is x,

so, the four consecutive numbers should be:

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According to the question,

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<h2>b)</h2>

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