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andrey2020 [161]
4 years ago
10

Please need help the review with my quiz on Thursday

Mathematics
2 answers:
eduard4 years ago
7 0

Answer:

ubpg

Step-by-step explanation:

Vlad1618 [11]4 years ago
4 0
B1 a3 c2 in think I just put something
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What is the prime factorization of 200?<br><br> 2 2 × 5 3<br> 2 3 × 5 2<br> 2 4 × 5<br> 2 × 5 4
Misha Larkins [42]

Answer:

2^3 * 5^2

Step-by-step explanation:

We need to break 200 down into prime numbers

200 = 20*10  These are not prime

       = 4*5  * 2*5    The 4 is not prime

       = 2*2*5  * 2*5  This is prime

Rearranging

       = 2*2*2*5*5

       = 2^3 * 5^2

8 0
3 years ago
Betty bought two bags full of books at an annual library book sale. If she
almond37 [142]

Answer:

12.90= .90+ 2x

12=2x

6=x

Each bag of books cost was $6

4 0
3 years ago
Read 2 more answers
Pls help me
Aneli [31]

Answer:

The answer would be 15. Your welcome my good sir

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A forester studying diameter growth of red pine believes that the mean diameter growth will be different from the known mean gro
-Dominant- [34]

Answer:

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

Step-by-step explanation:

Data given and notation  

\bar X=1.6 represent the sample mean

s=0.46 represent the sample deviation

n=32 sample size  

\mu_o =1.35 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 1.35 in/year, the system of hypothesis would be:  

Null hypothesis:\mu =1.35  

Alternative hypothesis:\mu \neq 1.35  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{1.6-1.35}{\frac{0.46}{\sqrt{32}}}=3.07  

P-value  

The degrees of freedom are given by:

df =n-1= 32-1=31

Since is a two-sided test the p value would be:  

p_v =2*P(t_{31}>3.07)=0.0044  

Since the p value is a very low value we have enough evidence to conclude that true mean is significantly different from 1.35 in/year at any significance level commonly used for example (\alpha=0.01,0.05, 0.1, 0.15).

5 0
3 years ago
5. Find the lateral surface area of the net of<br> the cube.<br> 1.8 cm
igor_vitrenko [27]

<u>Given</u>:

Given that the side length of the cube is 1.8 cm

We need to determine the lateral surface area of the cube.

<u>Lateral surface area of the cube:</u>

The lateral surface area of the cube can be determined using the formula,

LSA=4a^2

where a is the side length.

Substituting a = 1.8 in the above formula, we get;

LSA=4(1.8)^2

Squaring the term, we get;

LSA=4(3.24)

Multiplying, we get;

LSA=12.96

Thus, the lateral surface area of the cube is 12.96 cm²

6 0
3 years ago
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