<span>Each team in the softball league plays each of the other teams exactly once. For every game, there is 2 team playing. The order is not important because A vs B is same as B vs A
So you just need to makes a combination of 2 that have a result of 21. If there is t number of teams, the number of matches would be:
tC2 = t!/2!(t-2)! = 21
</span>t! / (t-2)! = 21 *2
(t)(t-1)= 42
t^2 -t -42=0
(t-7)(t+6)
t=7 ; t=-6
Excluding the minus result, you got 7 teams.
The answer would be log base 2 of 6 over log base 2 of 3
First of all, you have to calculate slope of that,
m = (y2-y1)/(x2-x1) = (1-0)/(0+2) = 1/2
now, equation would be y-y1 = m(x-x1)
y-1 = 1/2(x-0)
y-1 = x/2
y = x/2+ 1
Idek sorry have a nice day
Answer:
It is D
Step-by-step explanation:
6 x 11 = 66
3 x 9 = 27
