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Burka [1]
3 years ago
13

Simplify: − 7( 21 − 16) + 3(9) (24 − 18)

Mathematics
2 answers:
Mekhanik [1.2K]3 years ago
6 0
The answer to the problem is 127
lukranit [14]3 years ago
6 0
The answer is 127. Have fun
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What’s the derivative of (2x+9)^3
larisa86 [58]

If f(x) = (2x+9)^3, f '(x) = 3(2x+9)^2*(2), or f '(x) = 6(2x+9)^2.  Here we used the power rule with chain rule to find the derivative.

8 0
3 years ago
Twice a number plus 6 is greater than 12 what's the inequalities​
Reika [66]
I’m pretty sure 2x+6>12 or if you need the simplified version, x>3.
3 0
2 years ago
Multiply; 0.001 x 0.00001​
GalinKa [24]

Answer:

0.000000001

Step-by-step explanation:

1/1000×1/100000= 1/100000000= 0.000000001

7 0
2 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 < t < 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
X increased by 10 is equal to 42
AysviL [449]

Answer:

x = 32

Step-by-step explanation:

x + 10 = 42, then you subtract 10 from both sides to get 32

6 0
2 years ago
Read 2 more answers
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